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ddd [48]
3 years ago
9

What experiment should I make using Gravitational Force? PLEASE HELP ME :)

Physics
1 answer:
Bogdan [553]3 years ago
8 0

You could try the "Spinning Bucket" or the "Center Of Gravity" experiment. There are plenty more that you could research! Hope this helped :)

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A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105m above the Earth, a package is dropped from a w
Luden [163]

Here it is given that initial speed of the package will be same as speed of the helicopter

v_i = 5.10 m/s

displacement of the package as it is dropped on ground

d = -105 m

acceleration is due to gravity

a = -9.8 m/s^2

now by kinematics

y = v* t + \frac{1}{2}at^2

-105 = 5.1 * t - \frac{1}{2}*9.8*t^2

4.9 t^2 - 5.1 t - 105 = 0

by solving above equation we have

t = 5.2 s

so it will take 5.2 s to reach the ground

7 0
3 years ago
An athlete whirls a 7.00 kg hammer 1.8 m from the axis of rotation in a horizontal circle, as
iogann1982 [59]

Answer:

A-500 N

Explanation:

The computation of the tension in the chain is shown below

As we know that

F = ma

where

F denotes force

m denotes mass = 7

And, a denotes acceleration

Now for the acceleration we have to do the following calculations

The speed (v) of the hammer is

v = Angular speed × radius

where,

Angular seed = 2 × π ÷ Time Period

So, v = 2 × π × r ÷ P

v = 2 × 3.14 × 1.8 ÷ 1

= 11.304 m/s

Now

a = v^2 ÷ r

= 70.98912 m/s^2

Now the tension is  

T = F = m × a

= 7 × 70.98912

= 496.92384 N

= 500 N

5 0
3 years ago
Place the gears in order from highest to lowest torque?
Trava [24]
60, 12, 24,48- ddfjjvdd
5 0
3 years ago
What volume of lead must be fastened underneath it to sink the wood in calm water so that its top is just even with the water le
astraxan [27]
The bouyancy force is:  

Since the wood-lead system is completely submerged, the bouyancy force 

 is FB = ĎwgVl + ĎwgVb, where Ďw is the density of water,Vl 

 is the volume of 

 the piece of lead and Vb is the volume of the wooden block. The weight of the

  combined lead and wooden block is: W = ĎlgVl + ĎbgVb. Since the system is 

 in equilibrium, the bouyancy force must be equal to the total weight: 

 ĎwgVl + ĎwgVb = ĎlgVl + ĎbgVb 

 now we can solve for the volume of lead: 

 ĎwgVl â’ ĎlgVl = ĎbgVb â’ ĎwgVb 

 Vl(Ďw â’ Ďl) = Vb(Ďb â’ Ďw) 

 Vl =   

 Ďbâ’Ďw 

 Ďwâ’Ďl   

 Vb 

 Now we substitute the values for the density of lead Ďl = 11.3 Ă— 103kg/m3  , 

 the density of the wood and the density of water Ďw = 1000kg/m3 

 . We get: 

 Vl =   

 600â’1000 

 1000â’11300 

 (0.6m Ă— 0.25m Ă— 0.08m) = 4.66 Ă— 10â’4m3
4 0
3 years ago
Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is t
Aliun [14]

kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case =  4 m/s

when m = 0.125 kg

KE = (0.5) m v² =  (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg

KE = (0.5) m v² =  (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg

KE = (0.5) m v² =  (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg

KE = (0.5) m v² =  (0.5) (0.500) (4)² = 4 J

6 0
3 years ago
Read 3 more answers
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