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3 years ago

What experiment should I make using Gravitational Force? PLEASE HELP ME :)

1 answer:

8 0

You could try the "Spinning Bucket" or the "Center Of Gravity" experiment. There are plenty more that you could research! Hope this helped :)

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A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls c

Dafna11 [192]

Answer:

8.3m/s

Explanation:

Given parameters:

mass of clay ball = 5kg

Speed of clay ball = 25m/s

mass of clay ball at rest = 10kg

speed of clay ball at rest = 0m/s

Unknown:

Velocity after collision = ?

Solution:

Since the balls stick together, this is an inelastic collision:

m1v1 + m2v2 = v(m1 + m2)

5(25) + 10(0) = v (5 + 10)

125 = 15v

v = 8.3m/s

7 0

2 years ago

What is the hardest fruit to open??

Airida [17]

Answer:

pizza

Explanation:

3 0

2 years ago

Read 2 more answers

Based on the image, which is not a wavelength?

ki77a [65]

The distance that is not a wavelength in the image is C to E.

<h3>What is wavelength?</h3>

Wavelength is the distance between two successive crests or two successive trough or crest to trough.

It is also the distance over which the wave's shape repeats.

Based on the image, the following are wavelengths;

A to E, this is wavelength because it is between a crest and a trough.
B to F, this is wavelength because it is between two successive crest.
D to H, this is wavelength because it is between two successive trough.

Thus, the distance that is not a wavelength in the image is C to E.

Learn more about wavelength here: brainly.com/question/10728818

4 0

2 years ago

Approximately how long is a light-year?

Roman55 [17]

C. is the correct response.

8 0

3 years ago

Read 2 more answers

In an experiment conducted using the Young's double-slit apparatus, the separation between the slits is 20 µm. A first-order con

jeka57 [31]

To solve this problem, we use the formula
λ = s sin θ
where s is the separation and θ is the angle interference
So,
λ = 20 x 10^-6 sin 2.5
λ = 8.72 x 10^-7 m

The required angle for the fourth order bright fringe is
θb = sin⁻¹ (4λ / s) = sin⁻¹ (4 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 10.04°

The required angle for the fourth order dark fringe is
θd = sin⁻¹ (4.5 λ / s) = sin⁻¹ (4.5 (8.72 x 10^-7 m)/ 20 x 10^-6 ) = 11.31°

6 0

3 years ago