Explanation:
The position vector r:

The velocity vector v:

The acceleration vector a:



Answer:
Explanation:
400 W = 400 J/s
300000 J / 400 J/s = 750 s or 12.5 minutes
Answer:
Let I and j be the unit vector along x and y axis respectively.
Electric field at origin is given by
E= kq1/r1^2 i + kq2/r2^2j
= 9*10^9*1.6*10^-19*/10^-6*(2i+ j)
= (2.88i + 1.44j)*10^-3 N/C
Force on charge= qE= 3*10^-19*1.6*(2.88i +1. 44 j) *10^-3
F= (1.382 i + 0.691 j) *10^-21
Goodluck
Explanation:
Answer:
THE BOHR SHIFT ON THE OXYGEN-HEMOGLOBIN DISSOCIATION CURVE IS PRODUCED BY CHANGES IN THE CONCENTRATION OF CARBON IV OXIDE.
Explanation:
The oxygen-hemoglobin dissociation curve shows the relationship between the saturated hemoglobin concentration and oxygen. It shows how the blood hold on to and releases oxygen. The Bohr shift can occur as a result of changes in concentration of carbon iv oxide and other factors such as acidity or pH, 2,3-bisphosphoglycerate, exercise, also temperature of the body. These factors contributes to the right or left shift on the curve. Carbon iv oxide prevents the binding of oxygen to the hemoglobin. The is because hemoglobin has the same binding site for both oxygen and carbon iv oxide. Carbon iv oxide increase also leads to a change in the pH of the blood through the formation of bicarbonate ion. Bicarbonate ion formation causes reduced acidity and therefore lead a shift in the dissociation curve for more of the carbon iv oxide to be excreted as hemoglobin's affinity for oxygen reduces. And when the concentration of carbon iv oxide is low in the plasma, acidity increases and this provides more affinity for oxygen by the hemoglobin.
-- Take a sample of the first fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
This gives you the density of the first fluid.
-- Take a sample of the second fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
This gives you the density of the second fluid.
You want their average ?
OK
-- Add (Density of the first fluid) + (Density of the second fluid).
-- Divide the sum by 2 .
Now you have the average of the two densities.
Note:
That's NOT necessarily the density of a mixture when you
pour some of fluid-1 and fluid-2 into a jar. The density of the
fluid in the jar is going to depend on how much of each fluid is
in there.
I started to calculate how much of each one has to be there in order
for the density of the mixture to be equal to the average of their two
densities. But then I sat up straight, asked myself "Why ? !" .
Then I stopped, and went into the kitchen and ate some meatloaf.