Answer:
1.25C
Explanation:
When capacitance is in series we add them like this: 1/Ctotal = 1/C1 +1/C2 + 1/C3.....
1/C = 1/2 + 1/5 + 1/10 = 5 + 2 + 1/10 = 8/10
C = 10/8 = 1.25
Capacitance = Charge/potential difference(Q/V)
1.25 = Charge/12
Total charge = 1.25 ×12 =15coulombs
Answer:
<h2>The pin's final velocity is 5m/s</h2>
Explanation:
Step one:
given data
mass of ball m1=5kg
initial velocity of ball u1=10m/s
mass of pin m2=2kg
initial velocity of pin u2= 0m/s
final velocity of ball v2=8m/s
final velocity of pin v2=?
Step two:
The expression for elastic collision is given as
m1u1+m2u2=m1v1+m2v2
substituting we have
5*10+2*0=5*8+2*v2
50+0=40+2v2
50-40=2v2
10=2v2
divide both sides by 2
v2=10/2
v2=5m/s
The pin's final velocity is 5m/s
It goes potential, then kinetic, then potential. So D.
Answer:
An atmosphere is the layers of gases surrounding a planet or other celestial body. Earth's atmosphere is composed of about 78% nitrogen, 21% oxygen, and one percent other gases
Answer:
1.2 s
Explanation:
We'll begin by calculating the length (i.e distance) of the ramp. This can be obtained by using pythagoras theory as illustrated below:
NOTE: Length of the ramp is the Hypothenus i.e the longest side.
Let the Lenght of the ramp be 's'. The value of x can be obtained as follow:
s² = 4² + 3²
s² = 16 + 9
s² = 25
Take the square root of both side
s = √25
s = 5 m
Thus the length of the ramp is 5 m
Next, we shall determine the final velocity of the ball. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Distance (s) = 5 m
Final velocity (v) =?
v² = u² + 2as
v² = 3² + (2 × 2 × 5)
v² = 9 + 20
v² = 29
Take the square root of both side
v = √29
v = 5.39 m/s
Finally, we shall determine the time taken for the ball to reach the final position. This can be obtained as follow:
Initial velocity (u) = 3 m/s
Acceleration (a) = 2 m/s²
Final velocity (v) = 5.39 m/s
Time (t) =?
v = u + at
5.39 = 3 + 2t
Collect like terms
5.39 – 3 = 2t
2.39 = 2t
Divide both side by 2
t = 2.39 / 2
t = 1.2 s
Thus, it will take 1.2 s for the ball to get to the final position.