Answer:
No solution
Step-by-step explanation:
Given:
and 
Solve both inequality separately.
Subtraction property of inequality




and
Addition property of inequality



Hence, the solution of the compound inequality intersection of both solutions.
Please find attachment for number line solution.
No solution
Answer:
The whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square is 6 ft
Step-by-step explanation:
Here we are required find the size of the sides of a dunk tank (cube with open top) such that the surface area is ≤ 160 ft²
For maximum volume, the side length, s of the cube must all be equal ;
Therefore area of one side = s²
Number of sides in a cube with top open = 5 sides
Area of surface = 5 × s² = 180
Therefore s² = 180/5 = 36
s² = 36
s = √36 = 6 ft
Therefore, the whole number dimension that would allow the student to maximize the volume while keeping the surface area at most 160 square = 6 ft.
The range is all real number greater than - 1
Answer:
608 ft
Step-by-step explanation:
(2(0.5bh)) + 2bh + bh