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ANTONII [103]
3 years ago
5

In which medium does sound travel faster

Physics
2 answers:
9966 [12]3 years ago
5 0

It travels fastest through solids.

iVinArrow [24]3 years ago
4 0

Answer:

Solids APEX Verified

Explanation:

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Mendel wanted to find out if the pattern of inheritance for one trait affected the pattern of inheritance for anther. What exper
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Answer is given below :

Explanation:

  • He tested the seed color and shape. At the same time Gregor Mendel focused his search on seed size, flower color, seed coat color, pod size, immature pod color, flower position and pea plant height.
  • To describe the results he drew, he coined the terms 'recessive' and 'dominant'.

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What are used to transfer electrical energy from a power plant all the way to a home? generators turbines power transformers pow
defon

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Power lines

Explanation:

Generators induce that current that runs the turbines

Turbines also induce currents from water waves that is transmitted.

Transformers change A.C to D.C or vice versa.

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A
malfutka [58]

Answer:

<em>The penny will hit the ground at 6.39 seconds</em>

Explanation:

<u>Free Fall</u>

The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:

\displaystyle y=\frac{gt^2}{2}

Where g=9.8\ m/s^2, and t is the time.

Solving for t:

\displaystyle t=\sqrt{\frac{2y}{g}}

Using the value y=200:

\displaystyle t=\sqrt{\frac{2*200}{9.8}}

t=6.39 sec

The penny will hit the ground at 6.39 seconds

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7 0
3 years ago
A projectile is fired with an initial speed of 65.2 m/s at an angle of 34.5º above the horizontal on a long flat firing range. (
Margarita [4]

Answer:

A) h = 69.58 m

D) v = 58.12 \frac{m}{s}  (Speed magnitude)

α = 22.49° (Speed direction above the horizontal)

Explanation:

Conceptual analysis:

To solve this problem we consider the following concepts:

1) The projectile in its movement describes a curved line called a parabola, therefore two coordinates are required to fix the position at each instant of time, since the movement is performed in the X-Y plane.

The initial velocity (Vo) is tangent to the trajectory at the initial point and can be broken down into two components, one vertical (Voy) and one horizontal(Vox):

V_{ox} =  V_{o}Cos\alpha _{o} Formula (1)

V_{oy} =  V_{o}Sin\alpha _{o} Formula (2)

Where:

Vo: Initial velocity in m/s

\alpha_{o}: Initial angle above the horizontal in grades

2) The formula to calculate its velocity at any vertical position(y) is as follows:

v_{y}^{2} = v_{oy}^{2} -2gy Formula (3)

Where:

v_{f}^{2}: Final speed component in vertical direction in m/s

v_{oy}^{2}: Initial speed component in vertical direction in m/s

g: acceleration due to gravity in m/s2

3) The formulas to calculate the projectile velocity components at any time (t) are:

v_{x} = v_{ox} Because the movement is uniform in the x direction (constant speed)

v_{y} = v_{oy}-g*t Formula (4)  Because the movement is uniformly accelerated in the y direction

Known information:

We know the following data:

v_{o} = 65.2 \frac{m}{s}

\alpha _{o} = 34.5º above the horizontal

g=9.8 \frac{m}{s^{2}}

Development of the problem:

Initial speed components(Vox, Voy), (Formula (1), Formula (2)

v_{ox} =  65.2*Cos34.5 = 53.7\frac{m}{s}

v_{oy} =  65.2*Sin34.5 = 36.93\frac{m}{s}

A) Maximum height (h):

When the projectile reaches its maximum height (h) ,the speed component Vy = 0, then, we replace this value in the Formula (3):

0=(36.93)^2-2*9.8*h

h=\frac{ (36.93)^2}{2*9.8} = 69.58 m

D) Speed of the projectile 1.50s after firing

We replace t=1.5 s in the formula(4)

v_{y} = 36.93-9.8*1.5 = 22.23 \frac{m}{s}

v_{x} = v_{ox} = 53.7 \frac{m}{s}

v = \sqrt{53.7^{2}+22.23^{2}} = 58.12 \frac{m}{s}  (Speed magnitude)

\alpha = tan^{-1} (\frac{v_{y}}{v_{x}}) =  tan^{-1} (\frac{22.23}{53.7})

α = 22.49° (Speed direction above the horizontal)

6 0
3 years ago
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