The answer is 24 J
F K =.25*8 N
= 2N
F = f k = 2 N
Since a = 0
W = f * s
2 N * 12 m = 24 J
The coefficient of friction is a ratio used to quantify the friction force among two gadgets when it comes to the everyday pressure this is keeping them collectively. The coefficient of friction is critical attention at some stage in material selection and floor requirement determination.
For instance, ice on steel has a low coefficient of friction – the 2 materials slide past each different without problems – whilst rubber on the pavement has an excessive coefficient of friction – the substances no longer slide past each other without difficulty.
The coefficient of friction is dimensionless and it does not have any unit. it is a scalar, meaning the direction of the force does not have an effect on the physical quantity. The coefficient of friction depends on the gadgets that are causing friction.
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Answer:
1081.9 J
Explanation:
In order to calculate how much energy is converted into thermal energy due to friction, we have to calculate the difference between the mechanical energy of the child at the top and at the bottom of the slide.
At the top of the slide, he is at rest, so its kinetic energy is zero, and so he only has gravitational potential energy. Therefore:
where
m = 24 kg is the mass of the child
g = 9.8 m/s^2 is the acceleration of gravity
h = 5 m is the height relative to the ground
At the bottom of the slide, the child has only kinetic energy, so its total energy is
where
v = 2.8 m/s is the final speed of the child
Therefore, the therma energy generated due to friction is equal to the difference between the initial and final energy:
This question involves the concepts of the induced emf, magnetic field, and angular frequency.
The maximum emf induced in the coil is "32.68 volts".
The following formula can be used to find out the induced emf in the coil.
But, for maximum induced emf sin function should have a value of 1. Therefore,
where,
E = induced emf = ?
N = No. of turns in the coil = 310 turns
ω = angular frequency = 12.2 rad/s
A = Area of coil = (0.075 m)(0.18 m) = 0.0135 m²
B = magnetic field = 0.64 T
Therefore,
<u>E = 32.68 volts</u>
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