Answer:
a
0.57g
b
20.52
c
28.5
Explanation:
a
The bottle weighs 80g with tablets
If the bottle alone weighs 23g, the tablets weigh 57g
100 tablets weigh 57g, 1 tablet weighs 0.57g
b
0.57g is one tablet, so to achieve 36 tablets we must multiply by 36
0.57 multiplied by 36 is 20.52
c
To find 50 tablets we can use the same method we used before or a slightly faster method
100 tablets is 57g, so all we have to do is halve to find 50
57 divided by 2 is 28.5
Answer:
For the bird moving in a straight line, the kinetic energy is one-half the product of the mass and the square of the speed: Ek=12mu2.
Weight = (mass) x (acceleration of gravity) .
On Earth, acceleration of gravity is 9.8 m/s² (rounded) .
650 N = (mass) x (9.8 m/s²)
Divide each side by (9.8 m/s²): 650 N / 9.8 m/s² = mass
Mass = 66.3 kilograms (rounded)
The correct answer is this one: "D) significantly more than 100 billion gallons ." Clouds dump around 100 billion gallons of water on rainforests each year. The amount of rain is evaporated from the rivers, lakes and surface of rainforests each year is significantly more than 100 billion gallons<span> </span>
Answer:
A. 
B. 
C. 
Explanation:
The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is
is the capacitance, 
is the common plate area, 
is the plate separation and 
is the permittivity of the material between the plates.
For air or free space, is 
called the permittivity of free space. In general, 
where 
is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum, 
.
The energy stored in a capacitor is the average of the product of its charge and voltage.
Its charge, 
, is related to its capacitance by 
(this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for 
,
A. Substituting for in ,
B. When the distance is 
,
C. When the distance is restored but with a dielectric material of dielectric constant, 
, inserted, we have
