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3 years ago

10

Identifying Relationships A population of rabbits evolves thicker fur in

1 answer:

nekit [7.7K]3 years ago

6 0

Yes! rabbits altered their development to be better accustomed to their habitat!

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Which of the following describes the greenhouse effect?

ankoles [38]

Earth's greenhouse gases trap heat in the atmosphere and warm the planet.

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3 years ago

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Determine whether each phrase describes carboxylic acids or esters.

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The right answer is b

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3 years ago

Which of the following are physical rather than chemical properties of hydrogen gas(H2)? Check all that applya. H2 gas does not

Setler [38]

Answer: a, b, d

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Examples of physical properties in the context included in the question are the following: • Temperature • Solubility • Resistivity • Conductivity • Density

3 0

3 years ago

(a) Calculate the density of a 374.5-g sample of copper if it has a volume of 41.8 cm3. (b) A student needs 15.0 g of ethanol fo

o-na [289]

<u>Answer:</u>

<u>For a:</u> The density of the sample of copper is $8.96g/cm^3$

<u>For b:</u> The volume of ethanol needed is 19.0 mL

<u>For c:</u> The mass of mercury is 340. grams

<u>Explanation:</u>

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$ ......(1)

<u>For a:</u>

Mass of copper = 374.5 g

Volume of copper = $41.8cm^3$

Putting values in equation 1, we get:

$\text{Density of copper}=\frac{374.5g}{41.8cm^3}\\\\\text{Density of copper}=8.96g/cm^3$

Hence, the density of the sample of copper is $8.96g/cm^3$

<u>For b:</u>

Mass of ethanol = 15.0 g

Density of ethanol = 0.789 g/mL

Putting values in equation 1, we get:

$0.789g/mL=\frac{15.0g}{\text{Volume of ethanol}}\\\\\text{Volume of ethanol}=\frac{15.0g}{0.789g/mL}=19.0mL$

Hence, the volume of ethanol needed is 19.0 mL

<u>For c:</u>

Volume of mercury = 25.0 mL

Density of mercury = 13.6 g/mL

Putting values in equation 1, we get:

$13.6g/mL=\frac{\text{Mass of mercury}}{25.0mL}\\\\\text{Mass of mercury}=(13.6g/mL\times 25.0mL)=340.g$

Hence, the mass of mercury is 340. grams

5 0

3 years ago

Can someone please help me on the second one? I have no idea what to do.

Aleks [24]

The reaction will produce 12.1 g Ag₂S.

<em>Balanced equation</em> = 2Ag + S ⟶ Ag₂S

<em>Mass of Ag₂S</em> = 10.5 g Ag × (1 mol Ag/107.87 g Ag) × (1 mol Ag₂S/2 mol Ag)

× (247.80 g Ag₂S/1 mol Ag₂S) = 12.1 g Ag₂S

8 0

4 years ago