According to the question, the determined melting point of the compound is 112.5-113.0oC. When the solidified compound was retried, the melting point was found to be 133.6-154.5oC. This greater range higher than 112°C is caused by reusing samples leads to errors.
A pure sample is known by its sharp melting point. A pure sample does not melt over a large range. We can see this in the predetermined melting points of the pure sample(112.5-113.0oC).
However, reusing a sample introduces errors because the pure sample may become contaminated leading to a larger and higher range of melting point (133.6-154.5oC) which is far above 112°C.
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Answer:
The answer to your question is:
Explanation:
Other sugars with the same chemical formula as Glucose:
Sugar Formula Description
Glucose C₆H₁₂O₆ It's the most abundant monosaccharide.
Mannose C₆H₁₂O₆ It's found in plants and some animals.
Fructose C₆H₁₂O₆ It's the sugar of fruits.
Galactose C₆H₁₂O₆ It's found in milk.
Answer:
The coefficients are 2 for H₂O and 1 for Ca(OH)₂.
Explanation:
Let's consider the following reaction.
Ca(OH)₂(aq) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂O(l)
According to the balanced equation, the molar ratio of H₂O to Ca(OH)₂ is 2:1. Using this conversion factor, we have the following proportion:
moles Ca(OH)₂. (2 mol H₂O ÷ 1 mol Ca(OH)₂) = moles H₂O
The answer is oxidation.
That is in the redox fueling reaction,
succinate + NAD ↔fumarate + NADPH, the succinate molecule is undergoing oxidation.
As succinate molecule is providing electrons to NAD, so that it can be reduced from NAD to NADPH. So it is losing electrons and undergoing oxidation.
So the answer is oxidation.