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hoa [83]
4 years ago
13

After the equation below has been balanced for a reaction in an acidic solution, what will the coefficients of the reactants and

products be, in order? h2o2 + feso4 + h2so4 fe2(so4)3 + h2o
Chemistry
1 answer:
Sophie [7]4 years ago
3 0
First, we have to start balancing the equation:

H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + H2O

we can see that the number of H atoms on the left side is 4 and on the right side is  2 so we have to make the number of H atoms are equal on both sides

so, we will put 2H2O instead of H2O

H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + 2H2O

we can see that number of O on the left side is 10 and on the right side 14

so we will put 2 FeSO4 instead of FeSO4

H2O2 + 2FeSO4 + H2SO4 → →Fe2(SO4)3 + 2H2O

∴ the coefficients of the reactants and products will be in order 1 2 1 1 2
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Se someten a combustion 0,452g de un compuesto de C,H y N de masa molecular 80. Al recoger el CO2 y el H2O producidas obtenemos
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Answer:

Fórmula empírica: C₂H₂N

Fórmula molecular: C₄H₄N₂

Explanation:

Un compuesto que contiene carbono hidrógeno y nitrógeno con fórmula CₐHₓNₙ es sometido a combustion produciendo:

CₐHₓNₙ + O₂ → aCO₂ + x/2 H₂O + nNO₂

Con la masa de dióxido de carbono y agua podemos encontrar las moles de carbono e hidrógeno y su aporte a los 0.452g de muestra que fueron puestos en combustión, así:

<em>Moles C:</em>

Moles C = Moles CO₂ = 0.994g CO₂ ₓ (1mol / 44g) = 0.0226 moles C

Masa C: 0.0226 moles C ₓ (12.01g / mol) = 0.271g Carbono hay en la muestra

<em>Moles H:</em>

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Masa H: 0.0226 moles H ₓ (1.01g / mol) = 0.023g Hidrógeno hay en la muestra

Así, la masa de nitrógeno en la muestra y sus moles son:

Masa N = 0.452g - 0.271g C - 0.023g H

Masa N = 0.158g Nitrógeno

Y su moles son:

0.158g ₓ (1 mol / 14.01g) = 0.0113 moles N

Con las moles de C, H y N podemos determinar la formula empírica que se define como: "La relación de números enteros más simple entre la cantidad de átomos presentes en una mólecula. Si usamos como base las moles de nitrógeno (Valor menor):

Relación H/N: 0.0226 mol / 0.0113 mol = 2

Relación C/N: 0.0226 mol / 0.0113 mol = 2

Relación N/N: 0.0113 mol / 0.0113 mol = 1

Así, la <em>fórmula empírica es:</em>

<h3>C₂H₂N</h3>

Esta fórmula empírica tiene una masa molar de:

2C = 2*12 g/mol = 24g/mol

2H = 2*1g/mol = 2g/mol

N = 14g/mol

24+14+2 = 40g/mol

Como la masa molecular del compuesto es 80g/mol (Dos veces la de la fórmula empírica, la <em>fórmula molecular es 2 veces la fórmula empírica:</em>

<h3>C₄H₄N₂</h3>
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