It's lone a little distinction (103 degrees versus 104 degrees in water), and I trust the standard rationalization is that since F is more electronegative than H, the electrons in the O-F bond invest more energy far from the O (and near the F) than the electrons in the O-H bond. That moves the powerful focal point of the unpleasant constrain between the bonding sets far from the O, and thus far from each other. So the shock between the bonding sets is marginally less, while the repugnance between the solitary matches on the O is the same - the outcome is the edge between the bonds is somewhat less.
<span>Solubility product constant (Ksp) is </span>applied to the saturated ionic solutions<span> which are in equilibrium with its
solid form. The solid is partially dissociated into its ions.</span><span>
For the BaF, the dissociation as follows;
BaF</span>₂(s) ⇄ Ba²⁺(aq)
+ 2F⁻(aq)
<span>
Hence,
Ksp = [Ba</span>²⁺(aq)] [F⁻(aq)]²
Answer:
Reliability. When a scientist repeats an experiment with a different group of people or a different batch of the same chemicals and gets very similar results then those results are said to be reliable. Reliability is measured by a percentage – if you get exactly the same results every time then they are 100% reliable.
Explanation:
Sorry, I only got one way.
Use Planck's equation (E=hv) to solve. where <span>frequency (v) of ultrviolet radiation is 6.8 × 1015 1/s. </span><span>
</span>The variable h is a
constant equal to 6.63 × 10-34 J·s
E= <span>(6.8 × 1015 1/s)x(</span>6.63 × 10-34 J·s)
The answer is D. oversaturated. The term to represent the solution contains more solid solute than saturated solution is supersaturated, not oversaturated.
