Answer:
The molarity is 1.33×10^-7M
Explanation:
15ppb = 15g of chlorobenzene/10^9g of solution × 1 mole of chlorobenzene/112.6g × 1g of solution/mL = 1.33×10^-10mol/mL × 1000mL/1L = 1.33×10^-7mol/L
Well, the region is facing the sun, and hardly points away for half of a year.
Answer:
Explanation:
<u>1. Word equation:</u>
- <em>mercury(II) oxide → mercury + oxygen </em>
<u>2. Balanced molecular equation:</u>
<u>3. Mole ratio</u>
Write the ratio of the coefficients of the substances that are object of the problem:
![2molHgO/1molO_2](https://tex.z-dn.net/?f=2molHgO%2F1molO_2)
<u>4. Calculate the number of moles of O₂(g)</u>
Use the equation for ideal gases:
![pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol](https://tex.z-dn.net/?f=pV%3DnRT%5C%5C%5C%5C%5C%5Cn%3D%5Cdfrac%7BpV%7D%7BRT%7D%5C%5C%5C%5C%5C%5Cn%3D%5Cdfrac%7B0.970atm%5Ctimes5.20L%7D%7B0.08206atm.L%2FK.mol%5Ctimes%20390.0K%7D%5C%5C%5C%5C%5C%5Cn%3D0.1576mol)
<u>5. Calculate the number of moles of HgO</u>
![\dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO](https://tex.z-dn.net/?f=%5Cdfrac%7B2molHgO%7D%7B1molO_2%7D%5Ctimes%200.1576molO_2%3D0.315molHgO)
<u>6. Convert to mass</u>
- mass = # moles × molar mass
- molar mass of HgO: 216.591g/mol
- mass = 0.315mol × 216.591g/mol = 68.3g
Answer:
d. Cl2
sorry if I'm wrong
Cl2, as shown in the picture should have electrons in both the atoms but, in the question, the electrons are only in one of the atoms.
hope it helps :)