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dusya [7]
2 years ago
11

Which has the greater density, 5 kg of lead or 10 kg of gold?

Physics
1 answer:
NARA [144]2 years ago
5 0
Gold is much heavier than lead. It is very dense. ... Therefore gold weighs 19.3 times as lead
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What is centripetal force that allows a car to move around a sharp curve in a roadway?
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<span> The centripetal force that allows a car to move around a sharp curve in a roadway is the frictional force between the tires of its wheels and the surface of the road. </span>
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Everyday high and low tides on earth will happen daily about ______________. *
Murrr4er [49]
I think every 6 hours would be correct
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2 years ago
How large a current would a very long, straight wire have to carry so that the magnetic field 2.20 cm from the wire is equal to
choli [55]
Biot-Savart Law - Magnetic field around a straight conductor carrying a current I.

B = μ_0 I/2πr

where:
B is strength of magnetic field in T.
μ_0 is permeability of free space = 1.25664 x 10^ -6 T-m/A.
I is current in A.
r is distance from conductor in m.

<span>So I = 2πrB /μ_0</span>
6 0
2 years ago
The weigth of a body decrease in a coal mine why?​
pychu [463]

Answer

Gravitational force is between two object caused by energy in mass. Here when you are in a mine the radius of the earth in case of calculating gravity is reduced to the length between you and the center.

This means the mass of earth is decreasing even though the distance is decreasing. Relative to the decrease in distance squared the decrease in the mass of the second object(earth) is more. As a result your weight decreases.

5 0
3 years ago
Read 2 more answers
Un cuerpo se lanza verticalmente hacia arriba con una velocidad de 13 m/s. ¿Cuánto tiempo tarda en alcanzar la altura máxima? a)
Elena L [17]

Answer:

D. 1.33 segundos.

Explanation:

El cuerpo es experimenta un movimiento en caída libre al modificarse su velocidad por efecto de la gravitación terrestre. Este cuerpo alcanza instantáneamente el reposo cuando se encuentra a su altura máxima, el tiempo puede obtenerse sabiendo la aceleración y las velocidades incial y final a partir de la siguiente ecuación cinemática:

v = v_{o}+g\cdot t

Donde:

v - Velocidad final del cuerpo, medida en metros por segundo.

v_{o} - Velocidad inicial del cuerpo, medida en metros por segundo.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

t - Tiempo, medido en segundos.

Ahora se despeja el tiempo:

t = \frac{v-v_{o}}{g}

Si v_{o} = 13\,\frac{m}{s}, v=0\,\frac{m}{s} y g = -9.807\,\frac{m}{s^{2}}, entonces:

t = \frac{0\,\frac{m}{s}-13\,\frac{m}{s}}{-9.807\,\frac{m}{s^{2}} }

t = 1.326\,s

Por ende, la respuesta correcta es D.

6 0
3 years ago
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