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maxonik [38]
3 years ago
6

A healthy breakfast should include foods from the Grains group, the Vegetables OR Fruits group, and the Dairy OR the Protein gro

up. * O True O False​
Physics
2 answers:
Aloiza [94]3 years ago
4 0

Answer:

True

I Had this before

inessss [21]3 years ago
3 0

Answer:

vry true

Explanation:

yes because ll thoes give you protien sorry for my bad spelling

You might be interested in
I REALLY NEED HELP WITH PHYSICS ASAP!!!<br>Vf^2 = v0^2 + 2a (xf - x0)<br><br><br>Solve for a
ELEN [110]

Answer:

a. solve for a

vf ^{2} = vo ^{2}  + 2a(xf - xo) \\ 2a(xf - xo) = vf^{2}    -  vo ^{2}   \\ a =  \frac{vf^{2} - vo^{2}  }{2(xf - xo)}    \\ a =  \frac{vf ^{2} - vo ^{2}  }{2xf - 2xo}

I hope I helped you ^_^

7 0
3 years ago
An object is traveling with a constant velocity of 5 m/s. How far will it have gone after 7 s?
kozerog [31]
<h3>Answer:</h3>

35 meters

<h3>Explanation:</h3>

<u>Data given;</u>

  • Velocity of an object = 5 m/s
  • Time taken = 7 s

We are required to calculate how far the object traveled.

  • We need to know that;

Velocity = Displacement ÷ time

  • Therefore;

Displacement = Velocity × time

                       = 5 m/s × 7 s

                      = 35 m

Therefore; the object traveled 35 meters

6 0
3 years ago
Describe two of Tesla's inventions that influenced<br> technology and are still in use today.
victus00 [196]
The remote control, and wireless transmissions
3 0
3 years ago
Students in an introductory physics lab are producing a region of uniform electric field by applying a voltage to two 20-cm-diam
earnstyle [38]

Answer:

69000 V

Explanation:

E = Electric field = 3\times 10^6\ V/m

d = Distance between plates = 2.3 cm

When we multiply the electric field strength and the distance between the plates of a capacitor we get the maximum voltage.

Maximum voltage is given by

V_m=Ed\\\Rightarrow V_m=3\times 10^6\times 2.3\times 10^{-2}\\\Rightarrow V_m=69000\ V

The highest voltage the students can use is 69000 V

4 0
3 years ago
two astronauts are taking a spacewalk outside the International Space Station the first astronaut has a mass of 64 kg the second
Fittoniya [83]

Answer:

Approximately 0.88\; {\rm m \cdot s^{-1}} to the right (assuming that both astronauts were originally stationary.)

Explanation:

If an object of mass m is moving at a velocity of v, the momentum p of that object would be p = m\, v.

Since momentum of this system (of the astronauts) conserved:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\end{aligned}.

Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 0 since the velocity of both astronauts was 0\!.

Therefore:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

The final momentum of the first astronaut (m = 64\; {\rm kg}, v = 0.8\; {\rm m\cdot s^{-1}} to the left) would be p_{1} = m\, v = 64\; {\rm kg} \times 0.8\; {\rm m\cdot s^{-1}} = 51.2\; {\rm kg \cdot m \cdot s^{-1}} to the left.

Let p_{2} denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be (p_{1} + p_{2}).

\begin{aligned} & p_{1} + p_{2} \\ &= (\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

Hence, p_{2} = (-p_{1}). In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (51.2\; {\rm kg \cdot m \cdot s^{-1}}) but opposite in direction (to the right versus to the left.)

Rearrange the equation p = m\, v to obtain an expression for velocity in terms of momentum and mass: v = (p / m).

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{51.2\; {\rm kg \cdot m \cdot s^{-1}}}{64\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{to the right})}{} \\ &\approx 0.88\; {\rm m\cdot s^{-1}} && (\text{to the right})\end{aligned}.

Hence, the velocity of the astronaut in question (m = 58.2\; {\rm kg}) would be 0.88\; {\rm m \cdot s^{-1}} to the right.

5 0
2 years ago
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