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3 years ago

What is/are the products in the chemical equation?

Physics

2 answers:

Gennadij [26K]3 years ago

8 0

$\huge{ \mathfrak{ \underline{ Answer }}}࿐$

The balanced Chemical equation for above reaction is :

$\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}$

The product formed here is $NH_3$ (Ammonia)

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$\#TeeNForeveR$

Alla [95]3 years ago

5 0

Answer:NH3

Explanation: product s are the result of the equation

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One end of a string 6.26 m long is moved up and down with simple harmonic motion at a frequency of 95 Hz . The waves reach the o

uranmaximum [27]

Answer:

Explanation:

Given

length of string $L=6.26\ m$

frequency $f=95\ Hz$

time taken by wave to reach at other end $t=0.5\ s$

speed of wave is given by

$v=\frac{length\ of\ string}{time\ taken}$

$v=\frac{6.26}{0.5}$

$v=12.52\ m/s$

wavelength of is given by

$\lambda =\frac{velocity}{frequency}$

$\lambda =\frac{12.52}{95}$

$\lambda =0.131\ m$

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3 years ago

Compare the relative strengths of the nuclear force and the electric force

Serggg [28]

Answer:

To establish this relationship we must examine the potentials that these forces create. The electrical potential is described by

Ve = k q / r

The potential for strong nuclear force is

Vn (r) = - gs / 4pir exp (-mrc / h)

Where gs is the stacking constant and r the distance between the nucleons,

We can compare these potentials where the force is derived from the relationship

E = -dU / dr

F = q E

Explanation:

6 0

3 years ago

Bucket?

Sergio039 [100]

Final velocity=2m/s

kinetic energy lost = 96J

Explanation:

This question is an example for total inelastic collision.

For this type of collision, the equation is,

Step1: Finding the velocity

m1v1+m2v2 =(m1+m2) vf $m_1v_1+m_2v_2 =(m_1+m_2) v_f$

4*8+12*0 = (4+12)v

32 = 16v

$v= frac{32}{16}$ = 2m/s

Step 2:Finding the kinetic energy

$Kinetic energy = \frac{1}{2}\times mv^2$

$\text{Kinetic Energy before collision} = \frac{1}{2} m_1v_1^2+\frac{1}{2}m_2v_2^2$

Kinetic Energy before collision= $\frac{1}{2}\times4\times8^2+\frac{1}{2}\times12\times0^2$

Kinetic Energy before collision= 128J

$\text{Kinetic Energy after collision} = \frac{1}{2} m_1v_1^2+\frac{1}{2}m_2v_2^2$

$\text{ Kinetic Energy after collision}= \frac{1}{2}\times4\times2^2+\frac{1}{2}\times1\times*2^2$

Kinetic Energy after collison= 32J

Step 3: Finding the kinetic energy lost

Kinetic Energy lost = Kinetic Energy after collision – Kinetic Energy before collision

Kinetic energy lost=128 -32

Kinetic energy lost=96J

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3 years ago

When plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a

Zielflug [23.3K]

The correct answer is (d.) mica washer. When a plug prongs are connected to the metal case of an appliance, a part that should always be placed next to the case is a mica washer. Mica washer are used as a window for any radiation detectors.

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3 years ago

Please help me answer this! ANSWER IN SCENTENCE FORMAT!!! :

kap26 [50]

The answer is
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3 years ago

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