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gtnhenbr [62]
3 years ago
14

What is/are the products in the chemical equation?

Physics
2 answers:
Gennadij [26K]3 years ago
8 0

\huge{ \mathfrak{  \underline{ Answer  }}}࿐

The balanced Chemical equation for above reaction is :

\mathrm{N_2 + 3H_2 \rightarrow 2NH_3}

The product formed here is NH_3 (Ammonia)

\\  \\  \\  \\  \\  \\

\#TeeNForeveR

Alla [95]3 years ago
5 0

Answer:NH3

Explanation: product s are the result of the equation

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In a scientific experiment, the variable manipulated or controlled by the experimenter is called the
miskamm [114]
Answer:
The variable manipulated or controlled by the experimenter is called the independent variable.

Example:
If the flow velocity at the bottom of a tank is measured by varying the height of water in the tank, we are measuring velocity as a function of water height.
Therefore,
water height  =  independent variable (controlled)
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Mathematically,
v = f(h)
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3 0
3 years ago
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A proton is accelerated from rest through a potential difference of 2.5 kV and then moves perpendicularly through a uniform 0.60
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Answer:

1.2cm

Explanation:

V=(2ev/m)^1/2

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5 0
3 years ago
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The lowest point in Death Valley is 85 m below sea level. The summit of nearby Mt. Whitney has an elevation of 4420 m.What is th
mario62 [17]

Answer:

\Delta E=2.87\times 10^6\ J

Explanation:

It is given that,

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Mass of the hiker, m = 65 kg

We need to find the change in potential energy. It is given by :

\Delta E=mg(h_f-h_i)

\Delta E=65\times 9.8(4420-(-85))

\Delta E=2869685\ J

or

\Delta E=2.87\times 10^6\ J

So, the change in potential energy of the hiker is 2.87\times 10^6\ J. Hence, this is the required solution.

5 0
3 years ago
Question 4 How much time does it take to walk 8 km north at a velocity of 3.8 km/h?​
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Given parameters:

Displacement = 8km

Velocity  = 3.8km/h

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time  = ?

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      Displacement  = velocity x time

Input the parameters:

              8  = 3.8  x time

 Time  = \frac{8}{3.8}   = 2.1s

The time taken is 2.1s

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A bullet is fired at an angle θ above the horizontal with an initial velocity of 800 m/s from the top of an 80 m high tower. Wha
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