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Oxana [17]
3 years ago
15

Check out the list of scientific names. These names all represent animals. These are all annals but they cannot reproduce fertil

e offspring with each other. What conclusion can be drawn from the past statement?
Physics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

None of the animals are from the same species

Explanation:

The exact question is as follows :

Given -

Felis catus

Sylvilagus audubonii

Parus inornatus

Euarctos americanus

Check out the list of scientific names. These names all represent animals. These are all animals but they cannot reproduce to produce fertile offspring with each other.

To find - What conclusion can be drawn from the past statement?

Solution -

The conclusion we can made from past statement is that - None of the animals are from the same species

Reason -

When two members of the same species reproduce, they produce fertile offspring.

According to the scientific names of the animals, there are different genus and species names.

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Two circular coils are concentric and lie in the same plane. The inner coil contains 110 turns of wire, has a radius of 0.014 m,
Hatshy [7]

Answer:

The current flowing through the outer coils is  

Explanation:

From the question we are told that

   The number of turn of inner coil is N _i  =  110 \  turns

    The radius of inner coil is  r_i  =  0.014 \ m

     The current flowing through the inner coil is  I_i  =  9.0 \ A

     The number of turn of outer coil is N_o  =  160 \ turns

     The radius of outer  coil is r_o  =  0.022\ m

For net magnetic field at the common center of the two coils to be  zero  the current flowing in the outer coil must be opposite to current flowing inner coil

   The magnetic field due to inner coils  is mathematically represented as

            B_i  =   \frac{N_i \mu I}{2 r_i}

     The magnetic field due to inner coils  is mathematically represented as

            B_o  =  \frac{N_o \mu I_o}{2 r_o}

Now for magnetic field at center to be zero

             B_o  =  B_i

So

         \frac{N_i \mu I_i}{2 r_i} =  \frac{N_o \mu I_o}{2 r_o}

=>      \frac{110 * 9}{2 *  0.014} =  \frac{160 *I_o}{2 0.022}

         I_o  = 9.72 \ A

6 0
3 years ago
What is the value of the thickness of the boundary layer at leading edge of the plate?
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Along the flow direction, the boundary layer's thickness varies. For ReT values between 260 and 780, the boundary layer thickness—defined as the depth at which the normalized concentration has a value of 1/e—ranges between 800 and 250 m.

<h3>What is the Boundary layer?</h3>
  • A boundary layer is the thin layer of fluid that forms immediately around a bounded surface in physics and fluid mechanics as a result of the fluid flowing along the surface.
  • A no-slip boundary condition is created as a result of the fluid and wall interaction (zero velocity at the wall).
  • After that, the flow velocity above the surface steadily rises until it reaches the bulk flow velocity again.
  • The term "velocity boundary layer" refers to the thin layer of fluid whose velocity has not yet recovered to that of the main flow.
<h3>What purpose does a boundary layer serve?</h3>
  • Because it is on the fluid's boundary, engineers refer to this layer as the boundary layer.
  • Many aerodynamics issues, such as wing stall, skin friction drag on an object, and the heat transfer that takes place in high-speed flight, depend heavily on the specifics of the flow within the boundary layer.

Learn more about Boundary layer here:

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7 0
1 year ago
What is single kind of organism that can reproduce on its own?
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A cell will reproduce on its own
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The graph shows the heating curve of water the X axis shows heat added overtime and Y axis shows the temperature identify the re
goblinko [34]

Answer:

liquid, solid, and gas. A heating curve shows how the temperature changes as a substance is heated up at a constant rate.

Explanation:

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How much heat is required to evaporate 0.15 kg of lead at 1750°C, the boiling point for lead? The heat of vaporization for lead
lara [203]

Answer:

Heat required = mass× latent heat Q = 0.15 × 871 ×

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