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Oxana [17]
3 years ago
15

Check out the list of scientific names. These names all represent animals. These are all annals but they cannot reproduce fertil

e offspring with each other. What conclusion can be drawn from the past statement?
Physics
1 answer:
Black_prince [1.1K]3 years ago
6 0

Answer:

None of the animals are from the same species

Explanation:

The exact question is as follows :

Given -

Felis catus

Sylvilagus audubonii

Parus inornatus

Euarctos americanus

Check out the list of scientific names. These names all represent animals. These are all animals but they cannot reproduce to produce fertile offspring with each other.

To find - What conclusion can be drawn from the past statement?

Solution -

The conclusion we can made from past statement is that - None of the animals are from the same species

Reason -

When two members of the same species reproduce, they produce fertile offspring.

According to the scientific names of the animals, there are different genus and species names.

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Find the position of the center of mass of the system of the sun and Jupiter? (Since Jupiter is more massive than the rest of th
8090 [49]

Answer:

r_{cm} = 0.074 m from the position of the center of the Sun

Explanation:

As we know that mass of Sun and Jupiter is given as

M_s = 1.98 \times 10^{30} kg

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distance between Sun and Jupiter is given as

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now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them

so we will have

r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}

r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}

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3 0
3 years ago
What happens to force when pressure is doubled?
san4es73 [151]

When the force on some area is doubled and the area doesn't change,
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7 0
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A charge of 7.2 × 10-5 C is placed in an electric field with a strength of 4.8 × 105 StartFraction N over C EndFraction. If the
barxatty [35]

Answer:

2.2 meters

Explanation:

Potential energy, PE created by a charge, q at a radius r from the charge source, Q,  is expressed as:

KE=\frac{kQq}{r}\     \ \ \ \ \ \ ...i

k is Coulomb's constant.

#The electric field,E at radius r is expressed as:

E=\frac{kQ}{r^2}\ \ \ \ \ \ \ \ \ \ ...ii

From i and ii, we have:

KE=Eqr

r=(KE)/Eq

#Substitute actual values in our equation:

r=\frac{75J}{(7.2\times 10^{-5}C)(4.8\times 10^5 V/m)}\\\\=2.1701\approx2.2\ m

Hence, the distance between the charge and the source of the electric field is 2.2 meters

7 0
2 years ago
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Answer:

Explanation:

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6 0
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