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ozzi
3 years ago
15

A man is picked up by a tornado and dropped a quarter mile away from his home. Even though authorities estimate that his body wa

s dropped at 30 mph he suffered no major injuries. What factors contributed to the fact that his body was able to withstand this drop?
Physics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

the factor that contributed to the fact that he was able to survive this fall is due to the fact that his body is made up of bone which are strong and his skeleton also protected all his vitals internal organs. His body went limp after he was knocked in the head when he fell, all of these made room allowing his muscles to relax and this gave his bones the opportunity to absorb the impact of the fall

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How does the angle of launch affect the kinetic energy of a rubber band?​
Lady_Fox [76]

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

3 0
3 years ago
What is the benefit of developing the atomic mass unit as a standard unit of mass?
Alexeev081 [22]

Answer:

The atomic mass unit is 1/12 of an atom of carbon 12, and is a very small amount to represent in kilograms:

1m_{u}=1.66054x10^{-27}kg

m_{u} is atomic mass unit.

This is why the benefits of the atomic mass unit is that it makes the representation of atomic masses easier in terms of the simplicity of the numbers that are used to represent the masses. Also using the atomic mass unit it is easier to compare the masses of different atoms, These numbers would be very small and would require negative powers of 10 to represent them, so it is more convenient to use the atomic mass unit.

3 0
2 years ago
A cylinder with rotational inertia I1 = 3.0 kg · m2 rotates clockwise about a vertical axis through its center with angular spee
erastova [34]

Answer:

ω = 1.83 rad/s clockwise

Explanation:

We are given:

I1 = 3.0kg.m2

ω1 = -5.4rad/s (clockwise being negative)

I2 = 1.3kg.m2

ω2 = 6.4rad/s  (counterclockwise being positive)

By conservation of the momentum:

I1 * ω1 + I2 * ω2 = (I1 + I2) * ω

Solving for ω:

\omega = \frac{I1 * \omega1 + I2*\omega2}{I1+I2}=-1.83rad/s

Since it is negative, the direction is clockwise.

8 0
2 years ago
You throw a ball straight down from an apartment balcony to the ground below. The ball has an initial velocity of 5.00m/s, direc
erik [133]
The height of the balcony may be calculated through the equation,
                                h = V₀t + 0.5gt²
where h is the height, V₀ is the initial velocity, g is the gravitational constant and t is time. Substituting the values given above,
                               h = (5 m/s)(2s) + 0.5(10 m/s²)(2 s)²
                                 h  = 30 m
Thus, the height of the balcony is 30 meters. 
5 0
3 years ago
In an electricity experiment, a 1.10 g plastic ball is suspended on a 56.0 cm long string and given an electric charge. A charge
Shalnov [3]

Answer:

Tension, T = 0.0115 N                      

Explanation:

Given that,

Mass of the plastic ball, m = 1.1 g

Length of the string, l = 56 cm

A charged rod brought near the ball exerts a horizontal electrical force F on it, causing the ball to swing out to a 21.0 degree angle and remain there. According to attached figure :

T\cos\theta=mg

T is tension in the string

T=\dfrac{mg}{\cos\theta}\\\\T=\dfrac{1.1\times 10^{-3}\times 9.8}{\cos(21)}\\\\T=0.0115\ N

So, the tension in the string is 0.0115 N.

8 0
3 years ago
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