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3 years ago

Please help with last two questions please

Physics

1 answer:

Brrunno [24]3 years ago

6 0

Answer:

I know only answer second.

Explanation:

An objective sports and heigh

a lens produces its image 12 cm high.

so the formula of magnification is image height upon object height.So,

12/4=3 Answer

hope it helps

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You obtain a 100-W light bulb and a 50-W light bulb. Instead of connecting them in the normal way, you devise a circuit that pla

lesantik [10]

Answer:

When they are connected in series

The 50 W bulb glow more than the 100 W bulb

Explanation:

From the question we are told that

The power rating of the first bulb is $P_1 = 100 \ W$

The power rating of the second bulb is $P_2 = 50 \ W$

Generally the power rating of the first bulb is mathematically represented as

$P_1 = V^2 R$

Where $V$ is the normal household voltage which is constant for both bulbs

$R_1 = \frac{V^2}{P_1 }$

substituting values

$R_1 = \frac{V^2}{100}$

Thus the resistance of the second bulb would be evaluated as

$R_2 = \frac{V^2}{50}$

From the above calculation we see that

$R_2 > R_1$

This power rating of the first bulb can also be represented mathematically as

$P_ 1 = I^2_1 R_1$

This power rating of the first bulb can also be represented mathematically as

$P_ 2 = I^2_2 R_2$

Now given that they are connected in series which implies that the same current flow through them so

$I_1^2 = I_2^2$

This means that

$P \ \alpha \ R$

So when they are connected in series

$P_2 > P_1$

This means that the 50 W bulb glows more than the 100 \ W bulb

3 0

4 years ago

17-<br> Find the magnitude of vector product \BxĀ| for A=– 23 +3Â and B = 2î – 3+ Å<br> vectors.

aksik [14]

Answer:

alam ko sagot pero mataas

8 0

3 years ago

Nerf this hbhbhbbhbbhbhbhbhbhbhb

Vanyuwa [196]

Answer:

.......................

Explanation:

what

6 0

3 years ago

Read 2 more answers

Please help! Will mark best answer!!

MA_775_DIABLO [31]

The answer is (A) hope it helps

7 0

3 years ago

Read 2 more answers

A student sits at rest on a piano stool that can rotate without friction. The moment of inertia of the student-stool system is 4

irina [24]

Here We can use principle of angular momentum conservation

Here as we know boy + projected mass system has no external torque

Since there is no torque so we can say the angular momentum is conserved

$mvL = (I + mL^2)\omega$

now we know that

m = 2 kg

v = 2.5 m/s

L = 0.35 m

I = 4.5 kg-m^2

now plug in all values in above equation

$2\times 2.5 \times 0.35 = (4.5 + (2\times 0.35^2))\omega$

$1.75 = [4.5 + 0.245]\omega$

$1.75 = 4.745\omega$

$\omega = 0.37 rad/s$

so the final angular speed will be 0.37 rad/s

4 0

3 years ago