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irina [24]
4 years ago
12

Will these balloons be repelled or attracted? Why?

Physics
1 answer:
Aliun [14]4 years ago
7 0
These balloons will be attracted, as you have shown in the picture, there are two positives, they are not in the same spot. when two of the same poles are put together, they rebel each other, since the two positive poles are not in the same area of the balloon, the balloons will attract each other. I hope this helps :)  
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Consider the three inclines shown in the figure. The vertical line is an incline with a 90° angle. (Inclines with 90° angles do
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The final speed of C is equal to that of B.

The travel time of A is less than that of B.

The final speed of B is equal to that of A.

The travel time of C is greater than that of B.

The final speed of A is equal to that of C.

The travel time of C is greater than that of A.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Consider the three inclines shown in the figure (attached below). The vertical line is an incline with a 90° angle. All three inclines are frictionless. Three small identical objects are released from the top of the inclines.

When the objects are at the same height, they travel with the same height. The travel time is directly proportional to the incline.

Thus, all the statements are completed.

Learn more about speed.

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4 0
2 years ago
A hot air balloon is traveling vertically upward at a constant speed of 2.8 m/s. When
swat32
<span>why is your formula x=? if i'm reading it right the formula is the height of the object at time t. That being the case, set your setup (which looks right) equal to 0 and solve for t. This will tell you how long it takes to hit the ground. Plug this value of t into the forumla -9.8t+2.8 and that will tell you the speed at time t.</span>
6 0
3 years ago
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On isolated ground receptacles, the metal yoke ____ integrally bonded to the equipment grounding terminal of the receptacle.
Ede4ka [16]

On isolated ground receptacles, the metal yoke is not allowed to be integrally bonded to the equipment grounding terminal of the receptacle.

Any device with two distinct switches or receptacles is a duplex device. It can be shaped to fit a Decora opening or a typical duplex plate opening. It should be noted that they can be combination devices with a switch/outlet, switch/pilot light, etc.

Because of grounding connection removal and receptacle, it is utterly undesirable to connect the two bare equipment grounding conductors together directly.

The equipment grounding conductor associated with those circuits must be connected to the box when circuit conductors are terminated on equipment inside a metal box to prevent unneeded current discharge.

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4 0
2 years ago
A 2000 Hz siren and a civil defense official are both at rest with respect to the ground. What frequency does the official hear
astra-53 [7]

Answer:

a)f_1 = 2070.6 Hz

b)f_2 = 1929.4 Hz

Explanation:

Apparent frequency of the siren is given as

f = \frac{v_{rel}}{\lambda}

as we know that the wavelength will remain the same as it is having originally

sowe know

\lambda = \frac{340}{2000}

\lambda = 0.17 m

a) Now when wind is blowing from source to official

so we have

v_{rel} = 340 + 12 = 352 m/s

so we have

f_1 = \frac{352}{0.17}

f_1 = 2070.6 Hz

b) Now when wind is from official to source

so we have

v_{rel} = 340 - 12 = 328 m/s

so we have

f_2 = \frac{328}{0.17}

f_2 = 1929.4 Hz

4 0
4 years ago
A parallel-plate, air-gap capacitor has a capacitance of 0.14 mu F. The plates are 0.5 mm apart, What is the area of each plate?
Marysya12 [62]

Answer:

7.9060 m²

8.57 Volts

5.142×10⁻⁶ Joule

1.2×10⁻⁶ Coulomb

Explanation:

C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F

d = Distance between plates = 0.5 mm = 0.5×10⁻³ m

Q = Charge = 1.2 μC = 1.2×10⁻⁶ C

ε₀ = Permittivity = 8.854×10⁻¹² F/m

Capacitance

C=\frac{\epsilon_{0}A}{d}\\\Rightarrow A=\frac{Cd}{\epsilon_{0}}\\\Rightarrow A=\frac{0.14\times 10^{-6}\times 0.5\times 10^{-3}}{8.854\times 10^{-12}}\\\Rightarrow A=7.9060\ m^2

∴ Area of each plate is 7.9060 m²

Voltage

V=\frac{Q}{C}\\\Rightarrow V=\frac{1.2\times 10^{-6}}{0.14\times 10^{-6}}\\\Rightarrow V=8.57\ Volts

∴ Potential difference between the plates if the capacitor is charged to 1.2 μC  is 8.57 Volts.

Energy stored

E=0.5CV²

⇒E = 0.5×0.14×10⁻⁶×8.57²

⇒E = 5.142×10⁻⁶ Joule

∴ Stored energy is 5.142×10⁻⁶ Joule

Charge

Q = CV

⇒Q = 0.14×10⁻⁶×8.57

⇒Q = 1.2×10⁻⁶ C

∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb

6 0
3 years ago
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