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enot [183]
3 years ago
11

Chloroform and ethyl alcohol have a denisty of 1.49 g/mL and 0.789 g/mL respectively. What volume of chloroform is required to m

atch the amount of mass in 150 mL of ethyl alcohol?
Chemistry
1 answer:
ioda3 years ago
5 0

Answer:

79.2 mL

Explanation:

Step 1: Given data

  • Density of chloroform (ρC): 1.49 g/mL
  • Density of ethyl alcohol (ρE): 0.789 g/mL
  • Volume of ethyl alcohol (VE): 150 mL

Step 2: Calculate the mass corresponding to 150 mL of ethyl alcohol

We will use the definition of density.

ρE = mE/VE

mE = ρE × VE

mE = 0.789 g/mL × 150 mL = 118 g

We want the mass of chloroform to match the mass of ethyl alcohol. Then, mC = mE = 118 g

Step 3: Calculate the volume corresponding to 118 g of chloroform

We will use the definition of density.

ρC = mC/VC

VC = mC/ρC

VC = 118 g/ (1.49 g/mL) = 79.2 mL

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A container of oxygen has a volume of 30.0 mL and a pressure of 72.5 psi. If the pressure of the oxygen gas is reduced to 28 psi
OLga [1]

Answer:

THE NEW VOLUME OF THE OXYGEN GAS AT 28 PSI FROM 72.5 PSI IS 0.078 L.

Explanation:

Initial volume of the oxygen in the container = 30.0 mL = 30 / 000 L = 0.03 L

Initial pressure of the oxygen = 72.5 psi =  1 psi = 6890 pascal

Final pressure = 28 psi

Final volume = unknown

First convert the mL to L and since both pressures are in similar unit that is psi; there is no need converting them to pascal or other standard unit of pressure. They cancel each other out.

This question follows Boyle's equation of gas laws and mathematically it is written as:

P1 V1 = P2 V2

Re-arranging by making P2 the subject of the formula, we have:

V2 = P1 V1 / P2

V2 = 72,5 * 0.03 / 28

V2 = 2.175 /28

V2 = 0.0776 L

The new volume of the oxygen gas at a change in pressure from 72.5 psi to 28 psi is 0.078 L.

8 0
3 years ago
Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).
Phantasy [73]

Answer: 6.38\times 10^{23} molecules of water are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles

The balanced chemical reaction is:

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O  

According to stoichiometry :

2 moles of Fe_2O_3 produce = 3 moles of H_2O

Thus 0.707 moles of Fe_2O_3 will produce=\frac{3}{2}\times 0.707=1.06moles  of H_2O  

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus 1.06 moles of H_2O contains = \frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23} molecules

5 0
3 years ago
Adding energy to a solid bar of gold may result in which of the following outcomes
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An increase in motion and less attraction between particles

4 0
3 years ago
Which data can be measure quantitavtively
Marianna [84]

Quantitative data is a type of data that can be measured using numbers or is dealt with objectively. These include various types of data like temperature, weight, length, prices, area, volume, etc. now these data can be measured quantitatively.

sorry if i'm wrong

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7 0
2 years ago
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How many moles are in 4g of hydrogen?​
Afina-wow [57]

Answer:

2 mole

Explanation:

Hydrogen has 2 atoms per molecule

8 0
3 years ago
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