Answer:
B) 0.0456
Explanation:
It is given that :
Rationale :
UCL = 480
LCL = 480
∴ Mean ,
The standard deviation of sample (Sn) = 11.55
Z (for UCL)
= 2
Similarly,
Z (for LCL)
= -2
Now using the z table for finding the confidence level between Z value of -2 and 2.
Confidence level = 0.4772 + 0.4772
= 0.9544
Risk (alpha) = 1 - confidence level
= 1 - 0.9544
= 0.0456
Here we have perfectly inelastic collision. Perfectly inelastic collision is type of collision during which two objects collide, stay connected and momentum is conserved. Formula used for conservation of momentum is:
In case of perfectly inelastic collision v'1 and v'2 are same.
We are given information:
m₁=0.5kg
m₂=0.8kg
v₁=3m/s
v₂=2m/s
v'₁=v'₂=x
0.5*3 + 0.8*2 = 0.5*x + 0.8*x
1.5 + 1.6 = 1.3x
3.1 = 1.3x
x = 2.4 m/s
Answer:
500 N
Explanation:
Given that,
The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.
At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.
x + 800 = 400 + 500 + 400
x + 800 = 1300
x = 1300 - 800
= 500 N
So, the reading in the right hand scale is 500 N.
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Answer:
h = 67.081 m
Explanation:
Given that,
The time taken by a person to fall down is, t = 2.2 s
The height of the cliff from the ground, h = ?
The distance that the person will fall through the time is given by the formula
S = 1/2 gt² m
Where,
g - acceleration due to gravity
Substituting the values in the above equation
S = 1/2 x 9.8 m/s² x (3.7 s)²
= 67.081 m
Therefore, the height of the cliff from the ground is, h = 67.081 m