6. 5.50 x 10- molecules of carbon dioxide to moles.
1 answer:
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Answer: 128 g/mol
Explanation:
Graham's law states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass of its particles.
Mathematically, that is:
Since, you know the ratio of two rates and the molar mass of one gas, you can calculate the molar mass of the other gas.
The molar mass of the oxygen molecule, O₂ = 2×16.0g/mol = 32.0 g/mol.
In the coming equations, I will use 32 g/mol for simplicity of writing.
So, the molecular mass of the unnknown gas is 128 g/mol.