6. 5.50 x 10- molecules of carbon dioxide to moles.

2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo

pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

Chemical reaction involved: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol) (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: $Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2$

To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:

$\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}$

$\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)$

$\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)$

Therefore, the Gibb's free energy change at 37° C (310.15 K): ΔG = (-2.45 kJ/mol)

4 0

3 years ago

2. A compound with the following composition by mass: 24.0% C, 7.0% H, 38.0% F, and 31.0% P. what is the empirical formula

Svetach [21]

Answer:

C₂H₇F₂P

Explanation:

Given parameters:

Composition by mass:

C = 24%

H = 7%

F = 38%

P = 31%

Unknown:

Empirical formula of compound;

Solution :

The empirical formula is the simplest formula of a compound. To solve for this, follow the process below;

C H F P

% composition

by mass 24 7 38 31

Molar mass 12 1 19 31

Number of

moles 24/12 7/1 38/19 31/31

2 7 2 1

Dividing

by the

smallest 2/1 7/1 2/1 1/1

2 7 2 1

Empirical formula C₂H₇F₂P

5 0

3 years ago

What is an extensive property that can be calculated?

padilas [110]

Answer: The property which depends on the quantity of the substance is called an extensive property. The free energy change for a reaction (Δ G) depends on the quantity of the substance and is therefore an extensive property. It shows the additive nature. The extensive property Δ G is easily calculated from the formula, ΔG = -nFE cell.

Explanation:

4 0

3 years ago

Zn(s) + 2 HCl(aq) —> ZnCl2(aq)

miv72 [106K]

Answer:

First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)

Zn + 2HCl ==> ZnCl2 + H2(g)

moles of H2 desired: PV = nRT

n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)

n = 0.409 mole H2 desired

moles Zn needed:

0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed

mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)

Explanation:people always get this wrong but i got you

4 0

3 years ago

Producer gas is a fuel formed by passing air over red-hot coke (amorphous carbon). What mass of a producer gas that consists of

Karolina [17]

Producer gas is a fuel that is produced by burning biomass with an air deficit passed over red-hot coke (amorphous carbon). This gas is nothing but a mixture of gases such as hydrogen (H), carbon monoxide (CO), carbon dioxide (CO₂) and nitrogen (N₂).

The equation of producer gas is as follows -

CO₂ + 2N₂ (air) → CO + 2N₂

ΔH = -27.06 kcal

We know that,

1 Ton = 1000 kg

Mass of coke needed to form producer gas = 1.75 tons = 1750 kg

Given values,

Carbon monoxide (CO) = 25%

Carbon dioxide (CO₂) = 5%

Nitrogen (N₂) = 70%

One mole of carbon dioxide reacts with two moles of nitrogen to form one mole of carbon monoxide and nitrogen (producer gas).

We know that, 1 ton (1000 kg) of coke produces 470 Nm³ of producer gas, i.e.

470 × 4.359 = 2048.73 kg

1000 kg of coke produces = 2048.73 kg of producer gas

∴ 1 kg of coke produces = 2048.73 ÷ 1000 kg of producer gas

∴ 1750 kg of coke produces = 2048.73 × 1750 / 1000 = 3585.28 kg of producer gas.

Percentage yield = 87%

= 3585.28 × 87/100

= 3119.19 kg of producer gas

= 3.44 tons

Learn more about coke here-

brainly.com/question/13105289

#SPJ4

7 0

2 years ago