Answer:
The answer to your question is ΔP = 1.57 atm
Explanation:
Data
moles = 1
volume = 0.5 L
Temperature = 22°C or 295°K
Pressure = ?
a) Ideal Gas
PV = nRT R = 0.082 atm L / mol°K
-Solve for P
P = nRT/V
P = (1)(0.082)(295)/ 0.5
P = 23.944/ 0.5
P = 47.9 atm
b) Van der Waals
(P + a/v²)(v - b) = RT
- Substitution
(P + 1.345/0.5²)(0.5 - 0.03219) = (0.082)(295)
- Simplification
(P + 5.38)(0.46781) = 24.19
P + 5.38 = 24.19/0.46781
P + 5.38 = 51.71
-Solve for P
P = 51.71 - 5.38
P = 46.33 atm
c) The difference between both Pressures is
ΔP = 47.9 - 46.33
= 1.57 atm
Answer:
hydroxide is the one because it is the one HAHAH
I think it’s B and why is everyone putting a bunch of links?
Answer:
is the value of the equilibrium constant for this reaction at 756 K.
Explanation:
Equilibrium concentration of 
![[COCl_2]=7.40\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCOCl_2%5D%3D7.40%5Ctimes%2010%5E%7B-4%7D%20M)
Equilibrium concentration of 
![[CO]=3.76\times 10^{-2} M](https://tex.z-dn.net/?f=%5BCO%5D%3D3.76%5Ctimes%2010%5E%7B-2%7D%20M)
Equilibrium concentration of 
![[Cl_2]=1.78\times 10^{-4} M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D1.78%5Ctimes%2010%5E%7B-4%7D%20M)
The expression of an equilibrium constant can be written as;
![K_c=\frac{[CO][Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
is the value of the equilibrium constant for this reaction at 756 K.
A continuous process by which rocks are created, changed from one form to another, destroyed, and then formed again into different types of rocks. But what really know is that it's a rocky situation.
