1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
bulgar [2K]
2 years ago
8

How many moles of water could you make with 0.5 mol of H2?

Chemistry
1 answer:
weqwewe [10]2 years ago
7 0

Answer:

0.5 mols of water

Explanation:

You might be interested in
Planet A is an inner planet with no moon and hardly any atmosphere. Planet B is an inner planet with no moon but with a dense at
postnew [5]
I think the answers are Mars and Venus
7 0
3 years ago
What is elastic energy? list two examples of where it is found?
Free_Kalibri [48]

Sling shot, Bow and arrow

elastic energy is like a rubber band kind of

8 0
3 years ago
Read 2 more answers
A cube of steel has dimension 0.2m x 02.m x 0.2m. What is the volume of the cube in cubic centimeters ?
drek231 [11]

Answer:

8000

Explanation:

0.2 x 0.2 x 0.2

then m to cm^3

7 0
3 years ago
At a certain temperature, the ph of a neutral solution is 7.43. what is the value of kw at that temperature? express your answer
Delvig [45]

The formula for Kw is:

Kw= [H]*[OH]

where [H] and [OH] are concentrations 

We are given the pH so we can calculate the [H] concentration from the formula:
pH=-log[H] 
7.43 = -log[H]

[H] = 3.715x10^-8 M

In neutral solution, [H] = [OH], therefore: 

<span>[OH]= 3.715x10^-8 M

Calculating Kw:

Kw = (3.715x10^-8)*( 3.715x10^-8)</span>

<span>Kw = 1.38 x 10^-15 </span>

7 0
3 years ago
What is the E°cell for the cell represented by the combination of the following half-reactions? ClO4–(aq) + 8H+(aq) + 8e– Cl–(aq
Vinvika [58]

Answer:

The E°cell for the cell represented by the combination of the given half-reactions is 0.398 V

Explanation:

Oxide-reduction reactions, also called redox, involve the transfer or transfer of electrons between two or more chemical species. In these reactions two substances interact: the reducing agent and the oxidizing agent.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The species that supplies electrons is the reducing agent (that is, it is that species that oxidizes, yielding electrons and increasing its positive charge, or decreasing the negative one causing the reduction of the other species) and the one that gains them is the oxidizing agent ( that is, it is that species that is reduced, capturing electrons and increasing its negative charge, or decreasing its positive charge, causing oxidation of the other species).

This is the type of reaction that occurs in this case.

ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

VO₂⁺(aq) + 2 H⁺(aq) + e⁻ ⇔ VO⁺(aq) + H₂O(l) E° = 0.991 V

In this case both are written as reductions, and their E ° values ​​as well. The species that has the greatest potential for reduction will be the species that will be reduced, that is, it will be the oxidizing agent. In this case, it will be the first half-reaction expressed.  Therefore, to obtain a reaction, the second semi-reaction must be reversed to be an oxidation, maintaining its constant value. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = 0.991 V

<em>E°cell=Ereduction - Eoxidation</em>

E°cell=1.389 V - 0.991 V

<em>E°cell=0.398 V</em>

Then <u><em>the E°cell for the cell represented by the combination of the given half-reactions is 0.398 V.</em></u>

Another way of thinking is that, by inverting the second semi-reaction to be an oxidation, the value of E ° is reversed in the sign, unlike the previous case in which it was constant. Then:

Reduction: ClO₄⁻(aq) + 8 H⁺ (aq) + 8 e⁻ ⇔ Cl⁻ (aq) + 4 H₂O(l) E° = 1.389 V

Oxidation: VO⁺(aq) + H₂O(l) ⇔ VO₂⁺(aq) + 2 H⁺(aq) + e⁻ E° = -0.991 V

In this case:

E°cell=Ereduction + Eoxidation=

E°cell=1.389 V + (-0.991 V)=1.389 V-0.991 V

<em>E°cell=0.398 V</em>

Note that the result obtained is the same. This indicates that either of the two ways proposed is correct, and you will use the one that is most comfortable for you.

4 0
3 years ago
Other questions:
  • Research is being carried out on cellulose as a source of chemicals for the production of fibers, coatings, and plastics. Cellul
    8·1 answer
  • Electrons spill in shells in the nucleous the closest shell (n=1) can contain the maximum of. Electrons
    9·1 answer
  • In a nuclear reaction, the energy released is equal to 5.4 x 1015 joules. Calculate the mass lost in this reaction. (1 J = 1 kg
    11·2 answers
  • Explain how the integumentary system plays a crucial role in the ability to maintain homeoestasis
    14·1 answer
  • The U.S. quarter has a mass of 5.67 g and is approximately 1.55 mm thick.
    7·1 answer
  • Which factors affect electronegativity?
    6·2 answers
  • How do I graph these question
    5·1 answer
  • Which of the following would DECREASE the rate of a reaction?
    10·1 answer
  • Drag the slider from January to December. Based on what you observe, do you think Barcelona has large temperature changes throug
    14·1 answer
  • 2. Describe How are the two forms of energy<br> carried by waves and matter related?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!