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bulgar [2K]
3 years ago
8

How many moles of water could you make with 0.5 mol of H2?

Chemistry
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

0.5 mols of water

Explanation:

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Thermochromic ink, for which new uses are appearing in the fashion industry, is able to do what?
neonofarm [45]
<span>Thermochromic ink is a  kind of material that takes advantage of thermochromism. In chemistry, this is where a substance changes hues when exposed varying kinds of temperature. In the fashion industry, these inks are used for creating different kinds of accessories, clothing and bag designs. </span>
6 0
3 years ago
What volume of a 6.67 m nacl solution contains 3.12 mol nacl??
natima [27]

The volume of a 6.67 m nacl solution that contains 3.12 mol nacl is 0.468.

You just need to follow this formula:

C = n / V

So, it will be

V = n / C

<span>    = 3.12 / 6.67 moles / Liter </span>

<span>     = 0.468 L</span>

6 0
3 years ago
Read 2 more answers
For each solute, identify the better solvent: water or carbon tetrachloride
Olin [163]
Do you mean which one out of water and carbon tetrachloride
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3 0
4 years ago
How would you prepare 100.0 ml of.400 m CaCl2 from a stock solution of 2.00 M CaCl2?
docker41 [41]
C₀=2 mol/l
c₁=0.400 mol/l
v₁=100.0 ml = 0.1 l

c₁v₁=c₀v₀

v₀=c₁v₁/c₀
v(H₂O)=v₁-v₀

v₀=0.1*0.400/2=0.02 l = 20 ml
v(H₂O)=100 - 20 = 80 ml

It is necessary to mix 20 ml of the feed solution and 80 ml of water.

4 0
4 years ago
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PLEASE HELP...with single replacement reaction w/ activity series
Blizzard [7]

Answer : The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

Explanation :

Single replacement reaction : A chemical reaction in which the more reactive element replace the less reactive element.

It is represented as,

A+BC\rightarrow AC+B

In this reaction, A is more reactive element and B is less reactive element.

As per question, when gold (IV) iodide react with bromine to give gold (IV) bromide and iodine.

The balanced chemical reaction will be:

AuI_4+2Br2\rightarrow AuBr_4+2I_2

8 0
3 years ago
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