<u>We are given:</u>
P1 = 3 atm T1 = 623 K <em>(350 + 273)</em>
P2 = x atm T2 = 523 K <em>(250 + 273)</em>
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<u>Solving for x:</u>
From the idea gas equation:
PV = nRT
since number of moles (n) , Volume (V) and the Universal Gas constant(R) are constants;
P / T = k (where k is a constant)
the value of k will be the same for a gas with variable pressure and temperature and constant moles and volume
Hence, we can say that:
P1 / T1 = P2 / T2
3 / 623 = x / 523
x = 523 * 3 / 623
x = 2.5 atm (approx)
Therefore, the final pressure is 2.5 atm
Answer:
d orbitals
Explanation:
Transition metals are generally known as d-block elements. The electronic configuration of all transition elements finish in a d-orbital weather they are first row, second row or third row transition elements. This is the thread that holds all the elements of the transition series together.
This is why elements of the transition series are generally called the d-block elements.
By Gay Lussacs law you can find the pressure. First both temperatures of Celsius must change to Kelvin by adding 273. Temperature one will be 308K and temperature 2 will be 258K
With this info, you can now find the pressure with Lussacs law
P1 = P2
— —
T1 T2
Pressure 1 is given which is 32 psi so just plug it all in and find P2
32 = x
—— ——
308 258
308x = 8256 (Cross multiply)
X = 26.8 (divide both sides by 308)
Answer is 26.8 PSI
This makes sense because as temperature increases pressure increases, as well as when temperature decreases, pressure decreases. Since it’s a colder day the pressure will be lower.
A solution is the answer to a problem
Answer:
magnitude means absolute value, so the one that is greastest, like |-7| and |4| even id |-7| is a negative number, but it is still the one farthest away from 0, so |-7| is greater than |4|.
That is the way to find the greatest magnitude, but because I don't know your numbers so I can not answer your question, but this is the way to solve for it.
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