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sladkih [1.3K]
3 years ago
6

Systems are classified as human-made or natural. Match each example to the correct type of system.

Chemistry
2 answers:
BabaBlast [244]3 years ago
8 0

Answer:

Explanation:

<u>Natural System:</u>

1. solar system

2. plant root system

3. human digestive system

<u>Human-Made System:</u>

1. telephone system

2. city transit system

3. water purification system

Sidana [21]3 years ago
3 0

Answer: Here is the answere with a picture view for better understanding.

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Which conversion factor do you use first to calculate the number of grams of CO2 produced by the reaction of 50.6 g of CH4 with
zlopas [31]

Answer:

This is the conversion factor, we have to use:

44 g / 1mol

Explanation:

The reaction for the methane combustion is:

CH₄ + 2O₂  →  CO₂  +  2H₂O

First of all we use this conversion factor to determine the moles of methane, we used.

50.6 g . 1 mol / 16 g = 3.16 mol

So ratio is 1:1, then 3.16 mol of methane will produce 3.16 moles of CO₂

To calculate the grams of produced dioxide:

3.16 mol . 44 g / 1mol = 139.04 g

5 0
3 years ago
Write the electronic configuration of iron in fecl2 and fecl3
Dovator [93]

Answer:

Electronic configuration of fe is

4s2,3d6

Explanation:

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8 0
3 years ago
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Help! How do you calculate mean time?
Rina8888 [55]
You would take the time taken in trial 1 plus the time taken in trial 2 plus the time taken in trial 3. then you would take that values and divide it by 3 to get your answer
3 0
3 years ago
Which is an element?
Black_prince [1.1K]

Answer:

B

Explanation:

An element is something on the periodic table <em>by itself</em>.

3 0
4 years ago
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How many grams of ZnCl2 will be produced from 26.0g of Zn and 42.0g of HCl. Round to three significant figures
makvit [3.9K]

<u>Answer:</u> The mass of zinc chloride produced in the reaction is 54.1 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For zinc:</u>

Given mass of zinc = 26 g

Molar mass of zinc = 65.4 g/mol

Putting values in equation 1, we get:

\text{Moles of zinc}=\frac{26g}{65.4g/mol}=0.397mol

  • <u>For HCl:</u>

Given mass of HCl = 42 g

Molar mass of HCl = 36.5 g/mol

Putting values in equation 1, we get:

\text{Moles of HCl}=\frac{42g}{36.5g/mol}=1.150mol

The chemical equation for the reaction of zinc and HCl follows:

Zn+2HCl\rightarrow ZnCl_2+H_2

By Stoichiometry of the reaction:

1 mole of zinc reacts with 2 moles of HCl

So, 0.397 moles of zinc will react with = \frac{2}{1}\times 0.397=0.794mol of HCl

As, given amount of HCl is more than the required amount. So, it is considered as an excess reagent.

Thus, zinc metal is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of zinc produces 1 mole of zinc chloride

So, 0.397 moles of zinc will produce = \frac{1}{1}\times 0.397=0.397moles of zinc chloride

Now, calculating the mass of zinc chloride from equation 1, we get:

Molar mass of zinc chloride = 136.3 g/mol

Moles of zinc chloride = 0.397 moles

Putting values in equation 1, we get:

0.397mol=\frac{\text{Mass of zinc chloride}}{136.3g/mol}\\\\\text{Mass of zinc chloride}=(0.397mol\times 136.3g/mol)=54.1g

Hence, the mass of zinc chloride produced in the reaction is 54.1 grams

7 0
3 years ago
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