Answer:
HELL I DON'T EATHIER
Step-by-step explanation:
Answer:
64
Step-by-step explanation:
Brainliest
Let
. Then
. Note that
.
Recall that for
, we have

This means that for
, or
, we have

Integrate the series to get


Add the who numbers: 4 + 2 = 6
You are correct, it's C. 6
Answer:
1. 8.4 in 2. 33.6
Step-by-step explanation: