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kaheart [24]
3 years ago
13

g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses

are moving to the right before they collide and the heavier mass is further right then the lighter mass. The lighter mass has an initial speed of 4m/s and the heavier mass has an initial speed of 2m/s to the right. What is the final speed and direction of each mass mass? Was the collision elastic or inelastic and why?
Physics
1 answer:
statuscvo [17]3 years ago
8 0

Answer:

v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

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Answer: C. Steel

Explanation: When a sound wave travels through a solid body consisting

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3 years ago
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Answer:

36kms

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6 0
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What is the mass of a man who accelerates 4 m/s2 under the action of a 200 N net force?
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Answer:

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m =  \frac{200}{4}  \\

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What is affected by an airplane's speed?
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Answer:

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Explanation:

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initial velocity of the fish, u₁ = 12 m/s

initial velocity of the boat, u₂ = 0

let the final velocity of the fish-boat after collision = v

Apply the principle of conservation of linear momentum for inelastic collision;

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v = 9600/2200

v = 4.36 m/s

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