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Zina [86]
3 years ago
6

Find mass of 3 moles of water​

Chemistry
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

54 g

Explanation:

1 mole of water = H2O

mass of 1 mole of H2O= mass of h2 + mass of o

= 2× mass of h +mass of o

= 2×1+16 =18 g

1 mole of water = 18g

3moles of water = 18×3g= 54g

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Since we assume both reactants have 1 equivalent of H+ and OH- ions, we can balance the moles out. The acid of concentration x will have (x M)(0.035 L) = 0.035x moles of acid. Meanwhile, for the base: (0.432 M)(0.0246 L) = 0.0106 moles of base. Since these must be equivalent:
0.035x = 0.0106x = 0.304 M

8 0
3 years ago
Bella observes that the gas-filled tire of her bicycle becomes a little deflated when she keeps the bicycle outside in cold weat
weqwewe [10]

The low temperature outside lowers the volume of the gas according to Charles' law because this law describes how a gas will behave at constant pressure. It shows that the volume of a given mass of a gas is directly proportional to the absolute temperature provided the pressure remains constant. An increase in temperature leads to an increase in volume while a decrease reduces the volume. This is due to the reduction in the distances traveled by the vibrating  particles of the gas because of the lost kinetic energy.

5 0
3 years ago
There are 50 fish in the pond that have tags. You catch 25 fish, and 5 of them have tags. What is the best estimate of the numbe
sergeinik [125]

Answer: 250


Explanation:


You work this problem by using proportions.


A proportion is the equalization of two ratios.


Here you assume that the ratio of fish with tags to total fish that you catch is the same than the ratio of fish with tags to total fish in the pond.


Mathematically:

  • 5 fish with tag / 25 fish = 50 fish with tag / x
  • 5 / 25 = 50 / x

Solve for x:

  • Multiplication property of equality: x × 5 = 50 × 25
  • Division property of equality: x = 50 × 25 / 5
  • Result: 250
8 0
3 years ago
Read 2 more answers
in order to decrease the freezing point of 500. g of water to 1.00° c how many grams of ethylene glycol (C2H602)must be added (K
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Answer:

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6 0
3 years ago
Suppose the half-life is 9.0 s for a first order reaction and the reactant concentration is 0.0741 M 50.7 s after the reaction s
bazaltina [42]

<u>Answer:</u> The time taken by the reaction is 84.5 seconds

<u>Explanation:</u>

The equation used to calculate half life for first order kinetics:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half-life of the reaction = 9.0 s

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{9}=0.077s^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}     ......(1)

where,

k = rate constant  = 0.077s^{-1}

t = time taken for decay process = 50.7 sec

[A_o] = initial amount of the reactant = ?

[A] = amount left after decay process =  0.0741 M

Putting values in equation 1, we get:

0.077=\frac{2.303}{50.7}\log\frac{[A_o]}{0.0741}

[A_o]=3.67M

Now, calculating the time taken by using equation 1:

[A]=0.0055M

k=0.077s^{-1}

[A_o]=3.67M

Putting values in equation 1, we get:

0.077=\frac{2.303}{t}\log\frac{3.67}{0.0055}\\\\t=84.5s

Hence, the time taken by the reaction is 84.5 seconds

6 0
3 years ago
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