Calculate the volume in liters of a 2.3*10^-6 mercury(I) chloride solution that contains of mercury(I) chloride . Round your ans
1 answer:
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<u>Answer:</u> The standard free energy change of formation of is 92.094 kJ/mol
<u>Explanation:</u>
We are given:
Relation between standard Gibbs free energy and equilibrium constant follows:
where,
= standard Gibbs free energy = ?
R = Gas constant =
T = temperature =
K = equilibrium constant or solubility product =
Putting values in above equation, we get:
For the given chemical equation:
The equation used to calculate Gibbs free change is of a reaction is:
The equation for the Gibbs free energy change of the above reaction is:
We are given:
Putting values in above equation, we get:
Hence, the standard free energy change of formation of is 92.094 kJ/mol
Answer:
100.8 °C
Explanation:
The Clausius-clapeyron equation is:
-Δ
Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'
Isolating for T2 gives:
(sorry for 'deltaHvap' I can not input symbols into equations)
thus T2=100.8 °C