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Misha Larkins [42]
3 years ago
15

What happens as a result of the kinetic energy of the particles in a liquid being comparable with the intermolecular attractions

between the particles?
A The particles do not move enough to change positions, so the liquid is not compressible.
B The particles move enough that they separate from one another and take the shape of their container.
C The particles do not move enough, so they are fixed in place, and the liquid has a fixed volume.
D The particles move enough that they are not fixed in place, and the liquid can flow.
Chemistry
2 answers:
sdas [7]3 years ago
6 0

Answer : Option D) The particles move enough that they are not fixed in place, and the liquid can flow.

Explanation : The kinetic energy of the particles are allowed to move freely and are in motion when in the liquid state whereas the intermolecular particles can just flow; as the intermolecular attractions between the particles allows the liquid to flow by giving them a force to flow.

marusya05 [52]3 years ago
4 0

Answer:

Option D) The particles move enough that they are not fixed in place, and the liquid can flow.

Explanation:

Took the test just now

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How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?
meriva

Answer:

\large \boxed{\text{77.4 mL}}

Explanation:

                Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

    V/mL:     249

c/mol·L⁻¹:  0.0443     0.285

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\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1  mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}

3. Calculate the volume of HCl

V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}

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