Answer:
CeO₂
Explanation:
Hello!
In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:
Now, we simply divide each moles by 0.03 as the fewest moles in the formula to obtain the simplest formula (empirical formula) of this oxide:
Thus, the formula turns out:
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Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:
In terms of mass, specific heat and temperature change is:
Now, solve for the final temperature, as follows:
Then, plug in the masses, specific heat and temperatures to obtain:
Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.
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Answer : The correct option is, (b) occur when there is more free energy in the reactants than the products.
Explanation :
Endergonic reactions : It i defined as the reaction in which the energy is absorbed during the reaction.
In endergonic reactions, the Gibbs free energy of product is lower than the reactants. That means, ΔG > 0 and the reaction is non-spontaneous.
Exergonic reactions : It i defined as the reaction in which the energy is released during the reaction.
In exergonic reactions, the Gibbs free energy of product is greater than the reactants. That means, ΔG < 0 and the reaction is spontaneous.
Hence, the endergonic reactions is occur when there is more free energy in the reactants than the products.
