Explanation:
It is given that,
Speed of the electron in horizontal region, 
Vertical force, 
Vertical acceleration, 
..........(1)
Let t is the time taken by the electron, such that,
...........(2)
Let 
is the vertical distance deflected during this time. It can be calculated using second equation of motion:
u = 0
So, the vertical distance the electron is deflected during the time is 0.426 mm. Hence, this is the required solution.
The pendulum has a kinetic energy of 330 J at the bottom of its swing.
when a pendulum oscillates, the energy at its highest point is wholly potential, since it is momentarily at rest at the highest point. The pendulum experiences acceleration which is directed towards the mean position, as a result of which its speed increases. It has maximum speed at the point which is at the bottom of its swing.
As the pendulum swings from the highest to the lowest point, the potential energy at the highest point is converted into kinetic energy.
If air resistance can be neglected, one can apply the law of conservation of energy, which states that the total energy of a system remains constant.
In this case, the potential energy of 330 J at the highest point would be equal to the kinetic energy at the bottom point.
Therefore, the kinetic energy at the bottom of its swing will be 330 J.
Answer:
A
Explanation:
neutrons have neutral charge, while electrons are outside the nucleus with a negative charge
PE = mgh
m = 60 kg
g = 10 m/s
h = X
_______
3000 = 60×10×X = 5 m
Given data:
Yan speed;
Christopher speed;
Christophe starts 30 s later than Yan. Therefore, Christophe takes 30 s less than Yan to reach the same distance.
Part (A)
The distance is given as,
Let both Yan and Christophe meet at d distance from the start position. Therefore,
Substituting all known values,
Therefore, 600 s after Yan's departure Christophe will join him.
Part (B)
The distance is given as,
Substituting all known values,
Therefore, Christophe joins Yan after 6.17 km from the start.
