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2 years ago

What affects the vertical velocity of a projectile over time?---

Physics

1 answer:

kobusy [5.1K]2 years ago

6 0

The vertical velocity is affected by the acceleration of gravity (ignoring the effects of air resistance usually)

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A 100-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a

olchik [2.2K]

Answer:

The force required is equal to $30\pi N$ .

Explanation:

We know that

Torque = force × perpendicular distance

= F × R = I× $\alpha$

I = M× $\frac{R^{2} }{2}$

From above equation $\alpha = \frac{FR}{I}$ .............. 1

We know that

$w=w_{o} +\alpha t$ ...........................2

Given that t= 2 sec

$w_{o} = 0$

$w=0.4 rev/s = 0.8\pi rad/s$

From equation 1 and 2 , we get

F = $\frac{wI}{RT}$ = $\frac{w\times m \times r}{2t}$

Upon substituting the above values we will be getting

F = $30\pi N$

3 0

3 years ago

Calculate the kinetic energy of a 5.0kg object moving at 4.0 m/s

Nana76 [90]

Answer:

The answer is

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

$KE = \frac{1}{2} m {v}^{2}$

where

m is the mass

v is the velocity

From the question

m = 5 kg

v = 4 m/s

The kinetic energy is

$KE = \frac{1}{2} \times 5 \times {4}^{2} \\ = \frac{1}{2} \times 5 \times 16 \\ = 5 \times 8$

We have the final answer as

Hope this helps you

3 0

3 years ago

A heavy rock is shot upward from the edge of a vertical cliff. It leaves the edge of the cliff with an initial velocity of 12 m/

jenyasd209 [6]

Answer:

The height of the building is 88.63 m.

Explanation:

Given;

initial component of vertical velocity, $v_i$ = 12 m/s sin 26° = 5.26 m/s

initial horizontal component of the velocity, $u_i$ = 12 m/s cos 26° =10.786 m/s

horizontal distance traveled by the rock, x = 40.4 m

time of flight is calculated as;

x = $u_i$ t

t = x / $u_i$

t = 40.4 / 10.786

t = 3.75 s

Determine the final vertical velocity of the ball;

$v_f = v_i + gt\\\\v_f = 5.26 + (9.8 *3.75)\\\\v_f = 42.01 \ m/s$

Determine the height of the rock;

$v_f^2 = v_i^2 + 2gh\\\\h = \frac{v_f^2 - v_i^2}{2g}\\\\ h = \frac{(42.01)^2 - (5.26)^2}{2*9.8}\\\\h = 88.63 \ m$

Therefore, the height of the building is 88.63 m.

5 0

3 years ago

Light with a wavelength of about 490 nm is made to pass through a diffraction grating. the angle formed between the path of the

polet [3.4K]

The number of lines per mm in the diffraction grating is 326.

<h3>What is diffraction grating?</h3>

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The given data in the problem is

$\rm \theta$ is the angle formed between the path of the incident light and the diffracted light = 9. 2°

λ is the wavelength of the light=490nm=4.9

N is the number of lines per mm in the diffraction grating=?

n is ordered = 1

The formula for the diffraction grating is;

$n \lambda = d sin\theta \\\\ d = \frac{n \lambda}{sin \theta } \\\\ d = \frac{1 \times 4.90 \times 10^{-7}}{sin 9.2^0 } \\\\ d=3.06 \times 10^{-6} \\\\ d=3.06 \times 10^{-3} \ mm$