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3 years ago

11

When and where did the first nuclear reactor generate electricity

1 answer:

masha68 [24]3 years ago

5 0

<h2>Answer: On December 20th, 1951 in Idaho, United States. </h2>

The world's first experimental nuclear power plant was the Experimental Breeder Reactor Number One (EBR-I), which was built in a desert in Idaho, United States.

This reactor made history when, on December 20th, 1951, four 200-watt light bulbs were illuminated by means of atomic energy, specifically by nuclear fission reaction.

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kirza4 [7]

Answer:

$W = 462.5 keV$

Explanation:

As we know that when electron moved in electric field then work done by electric field must be equal to the change in kinetic energy of the electron

So here we have to find the work done by electric field on moving electron

So we have

$F = qE$

$F = (1.6 \times 10^{-19})(1.85 \times 10^6)$

$F = 2.96 \times 10^{-13} N$

now the distance moved by the electron is given as

$d = 0.25 m$

so we have

$W = F.d$

$W = (1.6 \times 10^{-19})(1.85 \times 10^6)(0.25)$

$W = 7.4 \times 10^{-14} J$

now we have to convert it into keV units

so we have

$1 keV = 1.6 \times 10^{-16} J$

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3 years ago

Help me get a answer

daser333 [38]

Answer:

I think D sorry if I'm wrong

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2 years ago

After the terrorist attacks of September 11th, 2001, the National Center on the Psychology of Terrorism was founded to research

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Reposta letra C oppositions

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1 year ago

A 100 kg box sits on an incline held at rest by a very thin rope attached to another mass hanging as shown. The force of frictio

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If friction is acting along the plane upwards

then in this case we will have

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also for other side of hanging mass we have

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now we have

$100(9.8)sin\theta = 100 + 490$

$980sin\theta = 590$

$sin\theta = 0.602$

$\theta = 37 degree$

In other case we can assume that friction will act along the plane downwards

so now in that case we will have

$mgsin\theta + F_f = T$

also we have

$T = Mg = 50(9.8) N$

now we have

$100(9.8)sin\theta + 100 = 50(9.8)$

$980sin\theta + 100 = 490$

$980 sin\theta = 490 - 100$

$sin\theta = 0.397$

$\theta = 23.45 degree$

<em>So the range of angle will be 23.45 degree to 37 degree</em>

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3 years ago

Why is the mechanical advantage of using a single pulley always 1? Assume there’s no friction. A. The input force is in a differ

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The answer is D. The input force is equal to the output force.

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3 years ago

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