The SI unit of mass is the kilogram, and
the SI unit of force is the Newton.
Answer:A7.50kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of2.30s. Find the force constant of the spring.
N/m
Explanation:
Answer:
3.036×10⁻¹⁰ N
Explanation:
From newton's law of universal gravitation,
F = Gm1m2/r² .............................. Equation 1
Where F = Gravitational force between the balls, m1 = mass of the first ball, m2 = mass of the second ball, r = distance between their centers.
G = gravitational constant
Given: m1 = 7.9 kg, m2 = 6.1 kg, r = 2.0 m, G = 6.67×10⁻¹¹ Nm²/C²
Substituting into equation 1
F = 6.67×10⁻¹¹×7.9×6.1/2²
F = 321.427×10⁻¹¹/4
F = 30.36×10⁻¹¹
F = 3.036×10⁻¹⁰ N
Hence the force between the balls = 3.036×10⁻¹⁰ N
The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.
That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.
The value of g is determined by using the Newton's Universal Law of gravity:
F = G * m of Earth * m of body / (distance^2)
Wehre {G* m of Earth / (distance^2) } = g
G is a universal constant = 6.67 * 10 ^ -11 N*m^2 / kg^2
m of Earth = 5.98 * 10 ^ 24 kg
distance = radius of Earth + height of the body
Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.
If you take a mean radius of Earth of 6.37*10^6 m
you get
g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2
Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.
