U need to do it in cronological order
Please, you have to apply the formula below:<span>Q=c∗m∗Δt</span>where Q is the energy lost, c is the specific heat of water, m is the mass of water involved, so m=3.75 *10^-1 Kg c=4,184 J/(Kg*°C) delta t=37.5 °C
Taking density of water as 1000kg/m3. Mass of water would be 0.375kg. So, heat lost would be<span>H=mCDeltaT</span>H=0.375*4184*37.5 = 58837.5J
Answer:
Explanation:
a) The forward reaction is exothermic, hence when temperature is increased the equilibrium shift towards the reactants side to get rid of the excess energy. This will mean that more reactants are produced decreasing yield
b) There are a fewer number of moles of gas on the right side compared to the left side (Just count the coefficients before each compound) so a higher pressure will mean that the equilibrium will shift towards the products side in order to decrease the pressure. This will mean that more products are formed increasing yield
c) When something is powdered it's surface area to volume ratio increases. A higher surface area means that the particles around it have more area to work on so the frequency of collisions will increase increasing the rate of reaction. This is why iron is powdered.
Answer 0.5
when reporting calculations from sig figs, report the number of sig figs in the least accurate measurement
so
((2.0265-2.02)/2.0265) x 100.00
((2.0265/2.0265) - (2.02/2.03)) X 100.00
(1.0000 -0.995) X 100.00
0.005 X 100.00
0.5
Answer:
The value of Kc is 9.33 * 10^-17
Explanation:
Step 1: Data given
Temperature = 1000 K
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Step 2: Calculate Kc for N₂ (g) + 2 O₂ ⇌ N₂O₄
N₂O₄ (g) ⇌ 2 NO₂ (g) Kc = 1.5 * 10^6
2 NO₂ (g) ⇌ N₂O₄ (g) = 1/Kc = 1 / 1.5 * 10^6 = 6.67 *10^-7
N₂ (g) + 2 O₂(g) ⇌ 2 NO₂ (g) Kc = 1.4 * 10^-10
Kc = Kc1 * Kc2
Kc = (6.67 *10^-7) * (1.4 * 10^-10)
Kc = 9.33 * 10 ^-17
The value of Kc is 9.33 * 10^-17
