Answer:
C4H6 + 2HBr = C4H8Br2
Explanation:
Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.
Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.
Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.
The only bond that involves the complete transfer of electrons is ionic bonding.
A metal that does not have much care for its electrons, such as Sodium, Na, is willing to give up its electron more freely. And an atom that really cares about having electrons might be a gas such as chlorine, Cl. The Chlorine atom takes the electron from Sodium, and then the newly formed ions of Na+ and Cl- bond because they have equal and opposite charges and opposites attract. NaCl is formed.
Hydrogen bonds aren’t actually real bonds (I know, the name is deceptive)
Covalent bonds involve the sharing of electrons.
I’m pretty sure metallic bonds is a made-up term.
Explanation:
Zn + Sn3(PO4)4 = Zn3(PO4)2 + Sn - Balanced Chemical Equation
4.3 is limiting
is the answer
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Answer:
Mass = 0.697 g
Explanation:
Given data:
Volume of hydrogen = 1.36 L
Mass of ammonia produced = ?
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Solution:
Chemical equation:
3H₂ + N₂ → 2NH₃
First of all we will calculate the number of moles of hydrogen:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
1atm ×1.36 L = n × 0.0821 atm.L/mol.K × 273.15 K
1.36 atm.L = n × 22.43 atm.L/mol
n = 1.36 atm.L / 22.43 atm.L/mol
n = 0.061 mol
Now we will compare the moles of hydrogen and ammonia:
H₂ : NH₃
3 : 2
0.061 : 2/3×0.061 = 0.041
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 0.041 mol × 17 g/mol
Mass = 0.697 g
