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sesenic [268]
3 years ago
9

It is not just lab chemicals but also common household substances that can be classified as acidic, basic, and neutral materials

. This categorization is based on the concentration of hydrogen ion (H+), or hydronium ion (H3O+), and hydroxide ion (OH-) present in the solutions. Based on these ion concentrations, the pH or pOH can be calculated giving a quantitative assessment. Additionally, litmus paper or pH paper can be used to qualitatively determine if the solution is acidic, basic, or neutral. Red litmus paper turns blue in acid. Blue litmus paper turns red in base. pH paper gives a more precise pH number based on the color the pH paper turns when a small amount of solution is placed on the paper.
Most materials are either acidic or basic. Baking soda, bleach, codeine, detergent, egg whites, household cleaners, and seawater are basic because they have a high concentration of hydroxide ions in solution and pH above 7. Acid rain, beer, coffee, lemon juice, maple syrup, mouth wash, pickles, rain, soda, tea, tomatoes, and vinegar are acidic because they have a high concentration of hydrogen ions in solution and pH below 7. A few solutions have neutral pH due an equal concentration of hydrogen ions and hydroxide ions. Water is the only truly neutral substance but human blood, milk, plant food, saliva, and tofu are very close to neutral pH with nearly equal hydrogen ion and hydroxide ion concentration and pH near 7.

Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may display additional information when you click on them. Drag and drop each item into the correct column. Order does not matter.

Physics
1 answer:
Montano1993 [528]3 years ago
6 0

Acidic: coffee, orange juice , soft drink, vinegar

Basic: Antacid, Baking soda, Detergent, Lye, Milk of Magnesia

Neutral: water, Sugar, Table salt.

<u>Explanation:</u>

Acidic substances have high concentration of hydrogen ions and have pH value less than 7. Basic substances have high concentration of hydroxide ions and have pH value more than 7. Neutral substance have pH value 7. The concentration oh hydrogen ions and hydroxide ions is equal.

Salt is formed when a acid reacts with base in a neutralization reaction. Different types of salt are formed depending upon the concentration of hydrogen and hydroxide ions. Neutral salt is formed when concentration of hydrogen ion is equal to concentration of hydroxide ions.

Coffee, orange juice , soft drink, vinegar are acidic substances. Antacid, Baking soda, Detergent, Lye, Milk of Magnesia. water, Sugar, Table salt are neutral substances.

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cestrela7 [59]

Answer:

Volume of balloon =  1000 cm^3

Explanation:

 The head of a normal person can be assumed as a sphere with radius 10 cm.

 Volume of sphere =\frac{4}{3} \pi r^3, where r is the radius.

 We have approximate radius = 10 cm.

  Approximate volume of head =\frac{4}{3} \pi r^3=\frac{4}{3} *\pi* 10^3=4188cm^3

 In the given options the closest value to the approximate volume is 1000 cm^3.

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3 years ago
A train starts at rest in a station and accelerates at a constant 0.987 m/s2 for 182 seconds. Then the train decelerates at a co
algol [13]

Answer:

\displaystyle X_T=66.6\ km

Explanation:

<u>Accelerated Motion </u>

When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

\displaystyle V_f=V_o+a\ t

where a is the acceleration, and vo is the initial speed .

The train has two different types of motion. It first starts from rest and has a constant acceleration of 0.987 m/s^2 for 182 seconds. Then it brakes with a constant acceleration of -0.321 m/s^2 until it comes to a stop. We need to find the total distance traveled.

The equation for the distance is

\displaystyle X=V_o\ t+\frac{a\ t^2}{2}

Our data is

\displaystyle V_o=0,a=0.987m/s^2,\ t=182\ sec

Let's compute the first distance X1

\displaystyle X_1=0+\frac{0.987\times 182^2}{2}

\displaystyle X_1=16,346.7\ m

Now, we find the speed at the end of the first period of time

\displaystyle V_{f1}=0+0.987\times 182

\displaystyle V_{f1}=179.6\ m/s

That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0

\displaystyle V_o=179.6,a=-0.321\ m/s^2\ ,V_f=0

\displaystyle t=\frac{v_f-v_o}{a}=\frac{0-179.6}{-0.321}

\displaystyle t=559.5\ sec

Computing the second distance

\displaystyle X_2=179.6\times559.5\ \frac{-0.321\times 559.5^2}{2}

\displaystyle X_2=50,243.2\ m

The total distance is

\displaystyle X_t=x_1+x_2=16,346.7+50,243.2

\displaystyle X_t=66,589.9\ m

\displaystyle \boxed{X_T=66.6\ km}

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Answer:

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Explanation:

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