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2 answers:
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Answer:
the value of horizontal force P is 170.625 N
the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.
Explanation:
The first diagram attached below shows the free body diagram of the tool chest when it is sliding.
Let start out by calculating the friction force
where :
friction force
= coefficient of friction
= normal friction
Given that:
= 0.3
0.3
Using the equation of equilibrium along horizontal direction.
P - 0
P = 0.3 ----- Equation (1)
To determine the moment about point B ; we have the expression
0 =
where;
P = horizontal force
= normal force at support A
W = self- weight of tool chest
Replacing W = 650 N
0 =
Replacing for P in equation (1)
Plugging the value of in equation (2)
P =170.625 N
Thus; the value of horizontal force P is 170.625 N
b) From the second diagram attached the free body diagram; the free body diagram of the tool chest when it is tipping about point A is also shown below:
Taking the moments about point A:
-(P × 100)+ (W×35) = 0
P =
Replacing 650 N for W
P = 227.5 N
Thus; the value of horizontal force P, when the tool chest tipping about point A is 227.5 N
We conclude that the motion will be impending for the lowest value when P = 170.625 N and when P= 227.5 N
However; the value of horizontal force at P = 227.5 N is that the block moves to right and this motion is due to sliding.
