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A 55.50 g gas sample of a gas, at stp, has a volume of 15.0 l. calculate the molecular mass of the gas

natta225 [31]

Answer is: the molar mass of gas is 82.83 g/mol.
m(gas) = 55.50 g; mass of gas.
V(gas) = 15.0 L; volume of gas.
Vm = 22.4 L/mol; molar volume of gas on STP.
n(gas) = V(gas) ÷ Vm.
n(gas) = 15 L ÷ 22.4 L/mol.
n(gas) = 0.67 mol; amount of gas.
M(gas) = m(gas) ÷ n(gas).
M(gas) = 55.5 g ÷ 0.67 mol.
M(gas) = 82.83 g/mol.

3 0

3 years ago

Read 2 more answers

Which of:

shusha [124]

Answer:

1, 2, 3

Explanation:

Using a simple chemical reaction as an example;

2H2 + O2 --> 2H2O

1) number of atoms

In the reactant side (left side of the reaction), there are 4 Hydrogen atoms which is equal with the number of atoms in the product (right side of the reaction). In the reactant side, there are 2 oxygen atoms, same thing with the product side. This means it is conserved.

2) Number of electrons

The number of electrons are also balanced. Although there is sharing of electrons, This means it is conserved.

3) In a chemical reaction, the law of conservation of matter is obeyed. Since the number of atoms is conserved, the mass is also conserved.

4) numbers of molecules

Although this is true for some reactions, it is not always the case as seen in the reaction above. This means it is not conserved.

4 0

3 years ago

In yeast, ethanol is produced from glucose under anaerobic conditions. A cell‑free yeast extract is placed in a solution that co

12345 [234]

Answer:

650 mmol.

Explanation:

The equation for the fermentation of one mole of glucose is:

C₆H₁₂O₆ + 2 NAD⁺ + 2 ADP + 2 P i + 2 NADH → 2 EtOH + 2 ATP + 2 NADH + 2 NAD⁺

Since NAD⁺/NADH is used and regenerated, we can eliminate it from the equation:

C₆H₁₂O₆ + 2 ADP + 2 P i → 2 EtOH + 2 ATP

With the equation, we calculate the maximum amount of ethanol that could be obtained theoretically:

1000 mmol C₆H₁₂O₆ ------------ 2000 mmol EtOH

325 mmol C₆H₁₂O₆ ------------- x= 650 mmol EtOH

Therefore, the maximum amount of ethanol that could be produced is 650 mmol.

8 0

3 years ago

Give an example of each of the following: (a) a monatomic cation, (b) a monatomic anion, (c) a polyatomic cation,(d) a polyatomi

Zina [86]

Answer and Explanation:

(a) MONATOMIC CATION: Monatomic cation are those cation in which only one atom is present

Example : $Na ^+,Ca^2+$

(b) MONATOMIC ANION : Monatomic anion are those cation in which only one atom is present

Example : $Cl^-,N^{3-}$

(C) Polyatomic Cation : Polyatomic cations are those cation which contains more than one atom

Example : $NH_4^+,NO_3^-$

(C) Polyatomic Anion : Polyatomic anions are those cation which contains more than one atom

Example : $SO_3^{2-}PO_4^{2-}$

6 0

3 years ago

If the coefficient to its place in front of the product Tetraiodine nonaoxide ( i4o9), then how many atoms of each element must

faltersainse [42]

8 iodine atoms and 10 oxygen atoms. Good luck!

3 0

4 years ago