There is a balloon filled with 1 liter of methane, CH4 gas at STP and a balloon filled with one liter of hydrogen gas, H2 at STP
1 answer:
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According to Graham's Law of Diffusion," Diffusion of Gas is inversely proportional to square root of its Molecular Mass or Density".
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
----- (1)
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
rᵇ/rᵃ =
Or,
rᵇ/rᵃ =
As,
Ma = 275 g/mol
Mb = 205 g/mol
Putting Values in eq.1,
rᵇ/rᵃ =
rᵇ/rᵃ = 1.15
Result:
Perfume B will diffuse 1.15 times faster than Perfume A. Hence, Perfume B will be first smelled by the person.
<u>Answer:</u> The total volume of the gaseous products is 1044.29 L
<u>Explanation:</u>
We are given:
Volume of butane = 116 L
At STP:
22.4 L of volume is occupied by 1 mole of a gas
So, 116 L of volume will be occupied by = of butane
The chemical equation for the combustion of butane follows:
- <u>For carbon dioxide:</u>
By Stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide
So, 5.18 moles of butane will produce = of carbon dioxide
Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L
- <u>For water vapor:</u>
By Stoichiometry of the reaction:
2 moles of butane produces 10 moles of water vapor
So, 5.18 moles of butane will produce = of water vapor
Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L
Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L
Hence, the total volume of the gaseous products is 1044.29 L