The moon orbits the Earth once every 27.322 days. It also takes approximately 27 days for the moon to rotate once on its axis. As a result, the moon does not seem to be spinning but appears to observers from Earth to be keeping almost perfectly still.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
Can you get a better pic so i can read it
Answer:
F'=708.53 N
Explanation:
We have,
The lifting force, F, exerted on an airplane wing varies jointly as the area, A, of the wing's surface and the square of the plane's velocity, v. It means tat,
k is constant
If, A = 190 Ft², v = 220 mph, F = 950 pounds
Let's find k first from above data. So,
It is required to find the lifting force on the wing if the plane slows down to 190 miles per hour. Let F' is the new force. So,
So, the lifting force is 708.53 pounds if the plane slows down to 190 miles per hour.
Answer: 109.89 Nm
Explanation:
The maximum torque will be calculated as the force multiplied by the perpendicular distance. This will be:
Torque = force × perpendicular distance
torque = 333 × 0.33
= 109.89 Nm