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frez [133]
3 years ago
10

Plss answer the question in the picture.

Chemistry
1 answer:
Liono4ka [1.6K]3 years ago
3 0
Wishbsndx issns did
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A book is pushed off the edge of a table. At what point during the fall will the potential and kinetic energy be equal?
vfiekz [6]

Answer:

KE = PE at half the table Height:

Explanation

AT ANY POINT IN THE BOOK'S FALL,

TOTAL E = PE +KE

THE TOTAL E IS CONSTANT

Before the book is pushed off, the total energy is potential

TOT E=PE =MGH

BEFORE THE BOOK HITS THE GROUND, THE TOTAL E IS KINETIC

TOT=KE = MVXV/2

WHEN KE = PE

KE+PE =<u> MGH (STARTING ENERGY SINCE E IS CONSERVED)</u>

<u>OR PE+ PE = MGH</u>

<u>OR MGH' + MGH' =MGH</u>

<u>OR 2H' =</u>H

H' (NEW HEIGHT) =H/2

5 0
3 years ago
ANSWER AS SOON AS POSSIBLE PLEASE!!!! Which type of water represents the largest percentage of earths water?
antoniya [11.8K]

Answer:

im pretty sure its groundwater just read this and see the answer

Explanation:

The ocean holds about 97 percent of the Earth's water; the remaining three percent is found in glaciers and ice, below the ground, in rivers and lakes. Of the world's total water supply of about 332 million cubic miles of water, about 97 percent is found in the ocean.

5 0
3 years ago
Read 2 more answers
29. Cross-contamination occurs when
frutty [35]

have a nice day buddy but I can't help you

4 0
3 years ago
The freezing point (tf) for t-butanol is 25.50°c and kf is 9.1°c/m. Usually t-butanol absorbs water on exposure to the air. If t
padilas [110]

The mathematical expression is given as:

\Delta T = k_{f}m             (1)

where, \Delta T = depression in freezing point

k_{f} = molal freezing point.

Now, first calculate the \Delta T = 25.50^{o}C -24.59^{o}C

\Delta T= 0.91^{o}C

Substitute the values in equation (1), we get

0.91^{o}C = 9.1^{o}C/m \times  m  

m = \frac{0.91^{o}C}{9.1^{o}C/m}

= 0.1 molal or  \frac{0.1 moles of water}{kg of butanol}

Now,

In 0.1 moles of water = 1 kg of butanol

So, 11.9 g of butanol = 11.9 g butanol\times \frac{0.1 mol of water}{kg butanol}

Convert gram into kilogram, (1 kg =1000 g)

= 11.9 g butanol\times \frac{0.1 mol of water}{kg butanol}\times \frac{1 kg}{1000 g}

= 0.00119 mole

Mass of water present in sample = 0.00119 mole\times 18 g/mol

= 0.02142 g

Hence, grams of water present in the sample  = 0.02142 g


8 0
3 years ago
(b) Give an example of an atom with this most stable configuration:
blondinia [14]

Answer:

Neon

Explanation:

The most stable Atoms are from the elements on group 18 of the predictable.

8 0
4 years ago
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