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3 years ago

What is the kinetic energy of a 30 kg dog that is running at a speed of 8.6 m/s (about 19 mi/h)?

Physics

1 answer:

wolverine [178]3 years ago

6 0

Answer:

Uhm thags hsed

Explanation:

Dkrr

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The "lead" in pencils is a graphite composition with a Young's modulus of about 1 ✕ 10⁹ N/m². Calculate the change in length (in

sweet [91]

Answer:

0.701 mm.

Explanation:

From Hook's law,

Young modulus = Stress/Strain.

Stress = Force/area = F/A

Strain = ΔL/L.

Therefore,

γ = (F/A)/(ΔL/L)

γ = FL/ΔLA ...................... Equation 1

Where γ = Young's modulus, F = Force, L = Length of the pencil, ΔL = change in length of the pencil, A = cross sectional area.

Make ΔL the subject of the equation,

ΔL = FL/γA......................... Equation 2

But,

A = πd²/4......................... Equation 3

Where d = diameter

Substitute equation 3 into equation 2

ΔL = 4FL/γπd²................ Equation 4

Given: F = 4.9 N, L = 55 mm = 0.055 m, d = 0.7 mm = 0.0007 m, γ = 1×10⁹ N/m², π = 3.14.

Substitute into equation 4

ΔL = (4×4.9×0.055)/(1×10⁹×3.14×0.0007²)

ΔL = 1.078/1538.6

ΔL = 7.01×10⁻⁴ m.

ΔL = 0.701 mm.

4 0

3 years ago

How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?

Anon25 [30]

Answer:

5.98 m

Explanation:

$T=2\pi \sqrt\frac{L}{g}$

$T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2)$ = 11.15*4.6²/(4π²) = 5.98 m

5 0

2 years ago

Can you access an instance variable from a static method? explain why or why not.

marusya05 [52]

The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.

5 0

4 years ago

Will give 45 points to who ever solves this

Lubov Fominskaja [6]

Answer:

1. 230 kg...

W = m * g

W= 230 kg * 9.81 m/s^2

W= 2256,3 N

m= 230kg , W = 2256,3 N , g= 9.81 m/s^2

2. 887 N

W= m * g

887 N = m * 9.81 m/s^2

m= 90,42 kg

m= 90,42 kg, W = 887 N , g= 9.81 m/s^2

3. 420 kg

W= m * a

w= 420 kg * 9.81 m/s^2

w= 4120,2 N

m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2

4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.

w = m * g

55.5 N = 15 kg * g

a= 3,7 m/s^2

m = 15 kg , W= 55.5 N , g= 3,7 m/s^2

7 0

2 years ago

Read 2 more answers

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act.One acrobat has a mass of 60

earnstyle [38]

Answer:

1.36m/s

Explanation:

We are given that

Mass of one acrobat, $m_1=60 kg$

Mass of another acrobat, $m_2=50 kg$

$v_2=-3 m/s$

$v_1=5 m/s$

We have to find their velocity immediately after they grab onto each other.

The collision between two acrobat is inelastic

According to law of conservation of momentum

$m_1v_1+m_2v_2=(m_1+m_2)V$

Substitute the values

$60\times 5+50(-3)=(60+50)V$

$300-150=110V$

$V=\frac{300-150}{110}=1.36m/s$

4 0

3 years ago