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laiz [17]
3 years ago
6

A solid crystal of NH3 is Question 24 options: soft, low melting, a poor electrical conductor. soft, low melting, a good electri

cal conductor. hard, high melting, a good electrical conductor. hard, high melting, a poor electrical conductor. soft, high melting, a poor electrical conductor.
Chemistry
1 answer:
Mumz [18]3 years ago
5 0

Answer:

soft, low melting , a poor electrical conductor

Explanation:

In a solid crystal of NH3; there exist a covalent bonding in between the Nitrogen and the hydrogen atoms. Thus the NH3 solid crystal is soft due as a result of covalent bonding. Covalent bonds are formed between two or more atoms having zero or very small electronegativity difference.

However in a covalent bond, a low temperature of heat is sufficient in melting  solid crystals of NH3.

SImilarly,in NH3 , the crystal structures , the crystal lattice of NH3 are fixed . Hence , the remain a poor conductor of electricity as they partially dissociate into ions in water.

Thus; A solid crystal of NH3 is soft,have a  low melting and a poor electrical conductor.

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Bridget is in science class. Her teacher gives her two unknown substances and asks her to determine their relative pH. She place
pav-90 [236]

Answer:

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Explanation:

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4 0
2 years ago
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
3 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
Re-order each list of elements in the table below, if necessary, so that the elements are listed in order of decreasing electron
Artyom0805 [142]

Answer:

O, S, Te

Cl, Br, Se

Explanation:

Main group elements have an electronegativity that increases across a period (from left to right) and decreases down a group.

Each atom has its own value which you can find on the electronegativity chart.

Metals have low values

Nonmetals have high values

I'm your case:

O = 3.5

S = 2.5

Te = 2.1

Cl = 3.0

Br = 2.8

Se = 2.4

3 0
3 years ago
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