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sergeinik [125]
3 years ago
9

What is the difference between evaporation and boiling

Chemistry
2 answers:
Gekata [30.6K]3 years ago
8 0
Answer:

Evaporation is slower, occurs only from the surface of the liquid, does not produce bubbles, and leads to cooling. Boiling is faster, can occur throughout the liquid, produces lots of bubbles, and does not result in cooling.
vlabodo [156]3 years ago
5 0

Answer/Explanation:

Let's define both terms

Boiling: is defined as a process whereby the liquid state is turned into gaseous state at a specific boiling point. And it is a fast process.

Evaporation: is defined as a process whereby a natural process in which the increase in temperature or pressure causes liquid to change into gas.

Difference between boiling and evaporation

In boiling, temperature of the liquid remains constant. While in evaporation, temperature of the liquid reduces

In boiling, temperature is required only at boiling point while in evaporation, temperature occurs at any given temperature.

In boiling, bubbles are formed while in evaporation, bubbles are not formed.

In boiling, a source of energy is required while in evaporation, the surrounding supplies the energy required.

Boiling produces heat and does not lead to liquid cooling, evaporation leads to liquid cooling.

The molecules of the liquid move faster in boiling than in evaporation

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Periodic Table question: In what family would you classify hydrogen? Why?
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Alkali metals
Hydrogen only needs one more valence electron to fill it's out shell. So it belongs with the alkali metals.
4 0
3 years ago
Read 2 more answers
Considering the chart shown, at what temperature does the substance boil? 200ºC 1,200ºC 2,200ºC 2,400ºC
kodGreya [7K]

Answer:

The answer is 2,200ºC

Explanation:
I took the assignment for Edge, I don't think I can send the image because it might pick up on that and get reported, sorry!

The only other rationale that I have is that it's boiling because the graph shows that it's at a constant temperature/rate at 2,200ºC for quite a while. Typically when something boils, it stays at that constant rate of boiling, unless you turn the temperature up or it's finally able to peak..?

8 0
3 years ago
What is the electron configuration of Mn3+
Mumz [18]

Answer:

The electron configuration for a

Mn3+ ion is [Ar]3d4

Explanation:

4 0
3 years ago
What is the percent composition of MgO2H2
zhannawk [14.2K]

41.38 % Mg

55.17 % O

3.45 % H

Explanation:

What is the percent composition of magnesium hydroxide Mg(OH)₂?

To find the percent composition we follow the next algorithm.

First we calculate the molar mass of Mg(OH)₂:

molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2

molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole

Now we devise the next reasoning:

if in         58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H

then in   100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H

X = (100 × 24) / 58 = 41.38 % Mg

X = (100 × 32) / 58 = 55.17 % O

X = (100 × 2) / 58 = 3.45 % H

Learn more about:

percent composition

brainly.com/question/419592

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4 0
3 years ago
A hot piece of copper was dropped into 155 g of water at 23.6 °C and 2,100 J of energy was transferred to the water. What is the
BlackZzzverrR [31]

Answer:

26.8 °C

Explanation:

Step 1: Given and required data

  • Mass of water (m): 155 g
  • Energy transferred to the water (Q): 2100 J
  • Initial temperature of the water (T₂): 23.6 °C
  • Final temperature of the water (T₁): ?
  • Specific heat of water (c): 4.184 J/g.°C

Step 2: Calculate the final temperature of the water

We will use the following expression.

Q = c × m × (T₂ - T₁)

T₂ = 2100 J/(4.184 J/g.°C) × 155 g + 23.6 °C = 26.8 °C

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3 years ago
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