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sergeinik [125]
3 years ago
9

What is the difference between evaporation and boiling

Chemistry
2 answers:
Gekata [30.6K]3 years ago
8 0
Answer:

Evaporation is slower, occurs only from the surface of the liquid, does not produce bubbles, and leads to cooling. Boiling is faster, can occur throughout the liquid, produces lots of bubbles, and does not result in cooling.
vlabodo [156]3 years ago
5 0

Answer/Explanation:

Let's define both terms

Boiling: is defined as a process whereby the liquid state is turned into gaseous state at a specific boiling point. And it is a fast process.

Evaporation: is defined as a process whereby a natural process in which the increase in temperature or pressure causes liquid to change into gas.

Difference between boiling and evaporation

In boiling, temperature of the liquid remains constant. While in evaporation, temperature of the liquid reduces

In boiling, temperature is required only at boiling point while in evaporation, temperature occurs at any given temperature.

In boiling, bubbles are formed while in evaporation, bubbles are not formed.

In boiling, a source of energy is required while in evaporation, the surrounding supplies the energy required.

Boiling produces heat and does not lead to liquid cooling, evaporation leads to liquid cooling.

The molecules of the liquid move faster in boiling than in evaporation

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Electromagnetic waves will travel the SAME SPEED (speed of light) WITHIN a medium as it does WITHOUT a medium. Question options:
Marrrta [24]

Answer:

True

Explanation:

The speed that electromagnetic waves will travel within any medium is the same as those without a medium. The speed of electromagnetic wave is a constant and does not depend on the material of the medium.

  • Electromagnetic waves are waves that do not require a material medium for their propagation.
  • They are able to pass through vacuums and mediums with particles at constant speed.
  • It is mechanical waves whose speed is medium dependent.
  • Mechanical waves have varying speed based on the mediums they move through.
8 0
3 years ago
Combustion of 9.511 grams of c4h10 will yield ____ grams of CO2
Flauer [41]

Answer:

\boxed{28.81}

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      58.12                   44.01

           2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

m/g:     9.511

1. Moles of C₄H₁₀

\text{Moles of C$_{4}$H$_{10} $} = \text{ 9.511 g C$_{4}$H$_{10} $} \times \dfrac{\text{1 mol C$_{4}$H$_{10} $}}{\text{ 58.12 g C$_{4}$H$_{10} $}} = \text{0.1636 mol C$_{4}$H$_{10}$}

2. Moles of CO₂

The molar ratio is 8 mol CO₂:2 mol C₄H₁₀

\text{Moles of CO}_{2} =\text{0.1636 mol C$_{4}$H$_{10} $} \times \dfrac{\text{8 mol CO}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \text{0.6546 mol CO}_{2}

3. Mass of CO₂

\text{Mass of CO}_{2} = \text{0.6546 mol CO}_{2} \times \dfrac{\text{44.01 g CO}_{2}}{\text{1 mol CO}_{2}} = \textbf{28.81 g CO}_{2}\\\\\text{The combustion will form $\boxed{\textbf{28.81 g CO}_{2}}$}

8 0
3 years ago
Which one of the following polymer is prepared by condensation polymerization?
nikitadnepr [17]

The answer is Darcon my friend, have a fantastic day

8 0
3 years ago
Read 2 more answers
er solutions can be produced by mixing a weak acid with its conjugate base or by mixing a weak base with its conjugate acid. The
liubo4ka [24]

Answer:

You need to add 19,5 mmol of acetates

Explanation:

Using the Henderson-Hasselbalch equation:

pH = pKa + log₁₀ [base]/[acid]

For the buffer of acetates:

pH = pKa + log₁₀ [CH₃COO⁻]/[CH₃COOH]

As pH you want is 5,03, pka is 4,74 and milimoles of acetic acid are 10:

5,03 = 4,74 + log₁₀ [CH₃COO⁻]/[10]

1,95 = [CH₃COO⁻]/[10]

<em>[CH₃COO⁻] = 19,5 milimoles</em>

Thus, to produce an acetate buffer of 5,03 having 10 mmol of acetic acid, you need to add 19,5 mmol of acetates.

I hope it helps!

7 0
3 years ago
ACTIVIDAD 2:
Firlakuza [10]
I don’t understand your language sorry
5 0
3 years ago
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