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3 years ago

What is the difference between evaporation and boiling

2 answers:

8 0

Answer:

Evaporation is slower, occurs only from the surface of the liquid, does not produce bubbles, and leads to cooling. Boiling is faster, can occur throughout the liquid, produces lots of bubbles, and does not result in cooling.

vlabodo [156]3 years ago

5 0

Answer/Explanation:

Let's define both terms

Boiling: is defined as a process whereby the liquid state is turned into gaseous state at a specific boiling point. And it is a fast process.

Evaporation: is defined as a process whereby a natural process in which the increase in temperature or pressure causes liquid to change into gas.

Difference between boiling and evaporation

In boiling, temperature of the liquid remains constant. While in evaporation, temperature of the liquid reduces

In boiling, temperature is required only at boiling point while in evaporation, temperature occurs at any given temperature.

In boiling, bubbles are formed while in evaporation, bubbles are not formed.

In boiling, a source of energy is required while in evaporation, the surrounding supplies the energy required.

Boiling produces heat and does not lead to liquid cooling, evaporation leads to liquid cooling.

The molecules of the liquid move faster in boiling than in evaporation

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How much 6.0 m hno3 is needed to neutralize 39ml of 2 m koh

Sever21 [200]

Answer:

13mL

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

HNO3 + KOH —> KNO3 + H2O

From the balanced equation above, we obtained the following data:

Mole ratio of the acid (nA) = 1

Mole ratio of the base (nB) = 1

Step 2:

Data obtained from the question.

This includes the following:

Molarity of the acid (Ma) = 6M

Volume of the acid (Va) =?

Volume of the base (Vb) = 39mL

Molarity of the base (Mb) = 2M

Step 3:

Determination of the volume of the acid.

Using the equation:

MaVa/MbVb = nA/nB, the volume of the acid can be obtained as follow:

MaVa/MbVb = nA/nB

6 x Va / 2 x 39 = 1/1

Cross multiply to express in linear form

6 x Va = 2 x 39

Divide both side by 6

Va = (2 x 39)/6

Va = 13mL

Therefore, the volume of the acid (HNO3) needed for the reaction is 13mL

5 0

3 years ago

I need help please please

inna [77]

Answer:

B should be the answer, and ur low-key valid lol

Explanation:

6 0

3 years ago

What volume of a 6.67 M NaCl solution contains 3.12 mol NaCl

jonny [76]

What's the big M? Molecular weight or mol?

5 0

3 years ago

A gas mixture contains HBr, NO2, and C2H6 at STP.If a tiny hole is made in the container, which gas will effuse fastest?Which ga

MakcuM [25]

Explanation:

Molar mass of HBr = 81 g/mol

Molar mass of nitrogen dioxide gas = 46 g/mol

Molar mass of ethane = 30 g/mol

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So, the gas with least molar mass will effuse out fastest from the container and that is ethane gas.

The formula for average kinetic energy is:

$K.E=\frac{3}{2}kT$

where,

k = Boltzmann’s constant = $1.38\times 10^{-23}J/K$

T = temperature = 273.15 K ( at STP)

As we can see from the formula that kinetic energy depends upon only temperature of the gas molecule.

So, from this we can say that all the gas molecules have the same average kinetic energy at this temperature.

5 0

4 years ago

How many grams of KCN are in 10.0 ml of a 0.10 M solution?

attashe74 [19]

Explanation:

As it is known that molarity is the number of moles present in a liter of solution.

Mathematically, Molarity = $\frac{no. of moles}{Volume in liter}$

As it is given that molarity is 0.10 M and volume is 10.0 ml. As 1 ml equals 0.001 L. Therefore, 10.0 ml will also be equal to 0.01 L.

Hence, putting these values into the above formula as follows.

Molarity = $\frac{no. of moles}{Volume in liter}$

0.10 M = $\frac{no. of moles}{0.01 L}$

no. of moles = 0.001 mol

As molar mass of KCN is equal to 65.12 g/mol. Therefore, calculate the mass of KCN as follows.

No. of moles = $\frac{mass}{molar mass}$

0.001 mol = $\frac{mass}{65.12 g/mol}$

mass = 0.06152 g

Thus, we can conclude that 0.06152 grams of KCN are in 10.0 ml of a 0.10 M solution.

3 0

3 years ago