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jarptica [38.1K]
3 years ago
13

Assume that AGHIE ALMN. Which of the following congruence statements

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0

answers below

so you guys won’t get it wrong

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A rectangle is 2 4/5 M wide and 3 and 1/2 meters long what is its area
postnew [5]
2 4/5=14/5, 3 1/2=7/2
A=l*w
14/5*7/2=98/10
98/10=9 8/10, 9 4/5
A= 9 4/5

Answer: Its area is 9 4/5m^2
8 0
3 years ago
Read 2 more answers
(x^2 + x - 17) + (x − 4) divide using polynomial long division
Effectus [21]

Answer: x+5 with a remainder of 3 (can also be said as 3/x-4)

Step-by-step explanation: See attachment

6 0
2 years ago
Five times the sum of 3 and twice some numbers is 70. What is the number?
Anna11 [10]
Let x represent some number
Sum of 3 and twice some number = 3 +2x
Five times the sum of 3 and twice some number: 5(3+2x)

5(3+2x)=70
15+10x=70
Subtract 15 from both sides to have 10x by itself
10x=55
Divide 10 on both sides to get x by itself
x=55/10
x=5.5

Hope this helped
8 0
3 years ago
The base of a circular fence with radius 10 m is given by x = 10cos(t), y = 10sin(t). the height of the fence at position (x, y)
Karo-lina-s [1.5K]
The average height of the fence is 2 m; its length is 20π m. So, its 2-sided area is
  A = 2*(2 m)*(20π m) = 80π m² ≈ 251 m²

At 1 L/(100 m²), it will take 2.51 L of paint to paint both sides.
6 0
3 years ago
Problem PageQuestion Tony estimated the height of his office building to be 45ft. The actual height of his office building is 41
Leona [35]

Answer:

The absolute error is <u>4 ft</u> and percent error of Tony's estimate is <u>9.8%</u>.

Step-by-step explanation:

Given:

Tony estimated the height of his office building to be 45ft. The actual height of his office building is 41ft.

Now, to find the absolute error and the percent error of Tony's estimate.

The height of his office building = 45ft.

The actual height of his office building = 41 ft.

So, to get the absolute error:

<em>The height of his office building - the actual height of his office building</em>

45\ ft-41\ ft\\=4\ ft.

The absolute error = 4 ft.

Now, to get the percent error of Tony's estimate:

\frac{4}{41} \times 100

=0.0975\times 100

=9.75\%.

<em>Percent error of Tony's estimate rounding to nearest tenth = 9.8%.</em>

Therefore, the absolute error is 4 ft and percent error of Tony's estimate is 9.8%.

5 0
3 years ago
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