Answer:
I think its true
Step-by-step explanation:
The correct option will be : B) 6 cm.
<u><em>Explanation</em></u>
Suppose, the width of the rectangle is
cm.
As, the length is 6 cm longer than the width, so the length will be: 
<u>Formula for the Area of rectangle</u> is:
Given that, the area of a rectangle is 72 cm²
So....

Using zero-product property, we will get...
<em>(Negative value is ignored as width can't be negative)</em>
and

So, the width of the rectangle is 6 cm.
Answer:
10 yards 2 inches
Step-by-step explanation:
15 yd 5 in - 5 yd 3 in =
10 yards and 2 inches
Answer:
B
Step-by-step explanation:
Two times the quantity of a number minus 12.
Represent the number with the variable y.
The quantity of a number minus 12 is then: (y-12).
Two times this quantity is 2(y-12).
So the answer is 2(y-12), which is B.
Answer:
a) P(Y > 76) = 0.0122
b) i) P(both of them will be more than 76 inches tall) = 0.00015
ii) P(Y > 76) = 0.0007
Step-by-step explanation:
Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.
To find - (a) If a man is chosen at random from the population, find
the probability that he will be more than 76 inches tall.
(b) If two men are chosen at random from the population, find
the probability that
(i) both of them will be more than 76 inches tall;
(ii) their mean height will be more than 76 inches.
Proof -
a)
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
) >
)
= P(Z >
)
= P(Z >
)
= P(Z > 2.25)
= 1 - P(Z ≤ 2.25)
= 0.0122
⇒P(Y > 76) = 0.0122
b)
(i)
P(both of them will be more than 76 inches tall) = (0.0122)²
= 0.00015
⇒P(both of them will be more than 76 inches tall) = 0.00015
(ii)
Given that,
Mean = 69.7,
= 1.979899,
Now,
P(Y > 76) = P(Y - mean > 76 - mean)
= P(
)) >
)
= P(Z >
)
= P(Z >
))
= P(Z > 3.182)
= 1 - P(Z ≤ 3.182)
= 0.0007
⇒P(Y > 76) = 0.0007