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Black_prince [1.1K]
3 years ago
13

The operator of a space station observes a space vehicle approaching at a constant speed v. The operator sends a light signal at

speed c toward the space vehicle. What is the speed of the light signal as viewed from the space vehicle
Physics
1 answer:
GenaCL600 [577]3 years ago
5 0

Answer:

The speed of the light signal as viewed from the observer is c.

Explanation:

Recall the basic postulate of the theory of relativity that the speed of light is the same in ALL inertial frames. Based on this, the speed of light is independent of the motion of the observer.

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What are the effects/impacts of electromagnetism to our world??​
yaroslaw [1]

Answer: Here's your answer: The great uses of Electromagnetism in Life. Whatever powered devices we use, from table clocks to microwave ovens, have some form of electromagnetic principle involved in their functioning. It is electromagnetism which has given the flexibility for switching of/on electricity as required.

Explanation: Yw and mark me as brainiest

7 0
2 years ago
Read 2 more answers
A stone is thrown vertically upward with a speed of 18.0 m/s. How fast is it moving when it reaches a height of 11.0m? How long
steposvetlana [31]
Given: v0= 18.0 m/s, y0=0m, yf=11m, g=-9.81 m/s^2 

v0= initial velocity, vf= final velocity, y0= initial height, yf= final height, g= gravity, sqrt()= square root, ^2=squared 

vf^2=v0^2 + (2)(g)(yf-y0) 
vf^2=(18.0 m/s)^2+(2)(-9.81 m/s^2)(11 m-0m) 
vf^2=18.0 m/s)^2 + (-19.62 m/s^2)(11 m)
vf^2=(324 m^2/s^2) - (215.82 m^2/s^2) 
vf^2=108.18 m^2/s^2 
vf=sqrt(108.18 m^2/s^2) 
vf=10.4 m/s
8 0
3 years ago
A 67-kg base runner begins his slide into second base when he is moving at a speed of 3.6 m/s. The coefficient of friction betwe
USPshnik [31]

Answer:

434.16 Joules

Explanation:

u = Initial velocity

v = Final velocity

m = Mass of person

From work-energy theorem

KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow KE=\frac{1}{2}\times 67\times (3.6^2-0)\\\Rightarrow KE=434.16\ Joules

The runner loses 434.16 Joules of mechanical energy.

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow \mu mg=\frac{W}{s}\\\Rightarrow s=\frac{W}{\mu mg}\\\Rightarrow s=\frac{434.16}{0.7\times 67\times 9.81}\\\Rightarrow s=0.94364\ m

He slides 0.94364 m

4 0
3 years ago
The force required to compress a non-standard spring as a function of displacement from equilibrium x is given by the equation F
UNO [17]

Answer:

The equation which define the work done by spring is w = 45 x³ - 8 x²

Explanation:

Given as :

The force is the function of distance x

I.e F(x) = a x² - b x

where

a = 45 N/m²

b = 8 N/m

Now, Wok done = Force ×displacement

I.e W = F . ds

So , W = (a x² - b x) × x

or, W = (45 x² - 8 x) × x

Or, w = 45 x³ - 8 x²

So, the equation which define the work done by spring is w = 45 x³ - 8 x²

Hence The equation which define the work done by spring is w = 45 x³ - 8 x²  Answer

7 0
2 years ago
PROJECTILES!!! URGENT!! PLEASE HELP!!
vesna_86 [32]
Щоиоет * нок глаз задёргался глаз не видно что ли


В общем я
Ншл газ за зла и вечно совершает благо в этом смысле жизни в России не было :)
7 0
3 years ago
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