Answer:
a)48900 metros
b)0.36875 metros
c)75634 metros
d)9.876 metros
Explanation:
Hola, para resolver debemos convertir unidades utilizando equivalencias
a) 48.9 km
1 kilometro = 1000 metros
48.9 x 1000 = 48900 metros
b) 36.875 cm
1 centímetro =0.01 metros
36.875 x 0.01 = 0.36875 metros
c) 756,34 hm
1 hectómetro= 100 metros
756.34 x 100 = 75634 metros
d) 9876 mm
1 milímetro = 0.001 m
9876 x 0.001 = 9.876 metros
Answer:
the radius of the earth in himalayan region is greater than terai reagion. therefore, the value of 'g' at the poles is greater than the value of g at the equator. 12
Explanation:
plz mark as brainlist thx :)
Answer:
a) The rotational inertia when it passes through the midpoints of opposite sides and lies in the plane of the square is 16.8 kg m²
b) I = 50.39 kg m²
c) I = 16.8 kg m²
Explanation:
a) Given data:
m = 0.98 kg
a = 4.14 * 4.14
The moment of inertia is:
![I=mr^{2} \\r=\frac{a}{2} \\I=m(a/2)^{2} \\I=\frac{ma^{2} }{4}](https://tex.z-dn.net/?f=I%3Dmr%5E%7B2%7D%20%5C%5Cr%3D%5Cfrac%7Ba%7D%7B2%7D%20%5C%5CI%3Dm%28a%2F2%29%5E%7B2%7D%20%5C%5CI%3D%5Cfrac%7Bma%5E%7B2%7D%20%7D%7B4%7D)
For 4 particles:
![I=4(\frac{ma^{2} }{4} )=ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}](https://tex.z-dn.net/?f=I%3D4%28%5Cfrac%7Bma%5E%7B2%7D%20%7D%7B4%7D%20%29%3Dma%5E%7B2%7D%20%3D0.98%2A%284.14%29%5E%7B2%7D%20%3D16.8kgm%5E%7B2%7D)
b) Distance from top left mass = x = a/2
Distance from bottom left mass = x = a/2
Distance from top right mass = x = √5 (a/2)
The total moment of inertia is:
![I=m(\frac{a}{2} )^{2} +m(\frac{a}{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}+m(\frac{\sqrt{5a} }{2} )^{2}=\frac{12ma^{2} }{4} =3ma^{2} =3*0.98*(4.14)^{2} =50.39kgm^{2}](https://tex.z-dn.net/?f=I%3Dm%28%5Cfrac%7Ba%7D%7B2%7D%20%29%5E%7B2%7D%20%2Bm%28%5Cfrac%7Ba%7D%7B2%7D%20%29%5E%7B2%7D%2Bm%28%5Cfrac%7B%5Csqrt%7B5a%7D%20%7D%7B2%7D%20%29%5E%7B2%7D%2Bm%28%5Cfrac%7B%5Csqrt%7B5a%7D%20%7D%7B2%7D%20%29%5E%7B2%7D%3D%5Cfrac%7B12ma%5E%7B2%7D%20%7D%7B4%7D%20%3D3ma%5E%7B2%7D%20%3D3%2A0.98%2A%284.14%29%5E%7B2%7D%20%3D50.39kgm%5E%7B2%7D)
c)
![I=2m(\frac{m}{\sqrt{2} } )^{2} =ma^{2} =0.98*(4.14)^{2} =16.8kgm^{2}](https://tex.z-dn.net/?f=I%3D2m%28%5Cfrac%7Bm%7D%7B%5Csqrt%7B2%7D%20%7D%20%29%5E%7B2%7D%20%3Dma%5E%7B2%7D%20%3D0.98%2A%284.14%29%5E%7B2%7D%20%3D16.8kgm%5E%7B2%7D)
Answer:
A. 3.4 m
Explanation:
Given the following data;
Force = 56.7N
Workdone = 195J
To find the distance
Workdone is given by the formula;
Making "distance" the subject of formula, we have;
![Distance = \frac {workdone}{force}](https://tex.z-dn.net/?f=%20Distance%20%3D%20%5Cfrac%20%7Bworkdone%7D%7Bforce%7D%20)
Substituting into the equation, we have;
![Distance = \frac {195}{56.7}](https://tex.z-dn.net/?f=%20Distance%20%3D%20%5Cfrac%20%7B195%7D%7B56.7%7D%20)
Distance = 3.4 meters.
Answer:
D &B
Explanation:
Using Fleming right hand rule that States that if the fore-finger, middle finger and the thumb of left hand are stretched mutually perpendicular to each other, such that fore-finger points in the direction of magnetic field, the middle finger points in the direction of the motion of positive charge, then the thumb points to the direction of the force