All categories

3 years ago

Please help me !! thank you all

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Ok so basically.... 15^2= 9^2+ x^2

15*15

225= 81+x
-81. -81

144=x^2

12=X

Im pretty sure it’s right!
I used the formula A^2+B^2=C^2

You might be interested in

Pleaseeeeeeee help me

Juli2301 [7.4K]

Answer:

The answer is "The discriminant is positive"

Step-by-step explanation:

When the discriminant is positive there is two real solutions.

When the discriminant is equal to 0, there is one real solution.

When the discriminant is negative, there is no real number solutions.

8 0

3 years ago

HELP ASAP!!!!! PLEASE

german

Answer: imma say A

Step-by-step explanation: sorry if wrong

8 0

3 years ago

Complete the factoring: <br><br> 5x^2-40x=5x( )<br><br> A) x-8 B)8-x C)x^2-8 D) 8-x^2

dolphi86 [110]

Answer:

A) x-8

Step-by-step explanation:

$\mathsf{5x^2-40x=5x(x-8)}$

because

$\mathsf{5x(x-8)=5x\cdot x-5x\cdot8=5x^2-40x}$

4 0

3 years ago

I need helpppppppppp!!!!!!!!!!

Genrish500 [490]

Answer:

m MN = 70°

Step-by-step explanation:

∠MLN is an angle formed by the chords ML and LN and is calculated as

∠MLN = 0.5( m arc MN ), that is

35° = 0.5 arc MN ( multiply both sides by 2 )

arc MN = 2 × 35° = 70°

4 0

3 years ago

Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

morpeh [17]

The first step for solving this expression is to reduce the fraction with 11.
$\sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } }$
Now reduce the fraction with $x^{7}$ .
$\sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } }$
Reduce the fraction one more time with $y^{6}$ .
$\sqrt{ \frac{5}{ x^{4} y^{2} } }$
To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:
$\frac{ \sqrt{5} }{ x^{2} y}$
Since we cannot simplify this fraction any further,, the final answer is going to be $\frac{ \sqrt{5} }{ x^{2} y}$ .
Let me know if you have any further questions.
:)

3 0

3 years ago

Read 2 more answers