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Kobotan [32]
3 years ago
15

Disponemos de 514,5 g de ácido sulfúrico (H2SO4

Chemistry
1 answer:
EleoNora [17]3 years ago
8 0

Answer:

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Explanation:

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Drag each tile to the correct box.
ElenaW [278]

Explanation:

Wind turbines generate electricity by following simple principle. Moving wind transfers energy to the to the blades of the wind mill which results in spinning of the blades. These blades are connected to internal shaft which also starts spinning. This spinning of shaft generates electricity which is further distributed to electrical substations to provide electricity to homes and businesses.

Step 1: Wind moves the blades of the turbine.

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7 0
3 years ago
State one reason for the color change in beaker A
myrzilka [38]
Because it either acids or base
4 0
3 years ago
B. What useful functions do oxidation numbers
disa [49]

Explanation:

b. What useful functions do oxidation numbers  serve?

It is used to show oxidation and reduction (loss and gain of electrons)

b. How many molecules are in 1 mole of  molecules?

1 mole = 6.022 * 10^23 molecules

c. What is the name given to the number of  molecules in 1 mole?

Avogadro's Number of molecules

21. a. What is the molar mass of an element?

This is the mass of an element divided by the number of moles.

Molar mass = Mass / Number of moles

b. Write the molar mass rounded to two  decimal places of carbon, neon, iron and  uranium.

amu = Atomic Mass Unit

Carbon = 12.01 amu

Neon = 20.18 amu

Iron = 55.85 amu

Uranium = 238.03 amu

7 0
2 years ago
What is the balanced form of the chemical equation shown below?
Svetradugi [14.3K]

Answer:

D

Explanation:

Double Displacement reaction

Both sides are balanced with option D

3 0
3 years ago
Determine the molar mass of a compound that has a density of 0.1633 g/L at STP.<br> (show work)
hodyreva [135]

Answer:

                     M.Mass  =  3.66 g/mol

Data Given:

                  M.Mass  =  M = ??

                  Density  =  d  =  0.1633 g/L

                  Temperature  =  T  =  273.15 K (Standard)

                  Pressure  =  P  =  1 atm (standard)

Solution:

              Let us suppose that the gas is an ideal gas. Therefore, we will apply Ideal Gas equation i.e.

                                             P V = n R T    ---- (1)

Also, we know that;

                       Moles  =  n  =  mass / M.Mass

Or,                                   n  =  m / M

Substituting n in Eq. 1.

                                             P V = m/M R T   --- (2)

Rearranging Eq.2 i.e.

                                             P M = m/V R T   --- (3)

As,

                     Mass / Volume = m/V = Density = d

So, Eq. 3 can be written as,

                                             P M = d R T

Solving for M.Mass i.e.

                                             M = d R T / P

Putting values,

M  =  0.1633 g/L × 0.08205 L.atm.K⁻¹.mol⁻¹ × 273.15 K / 1 atm

M  =  3.66 g/mol

6 0
2 years ago
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