The neutralization reaction among all the reactions would be the one between an acid and a base to produce salt and water.
<h3>What is a neutralization reaction?</h3>
It is a reaction involving an acid and a base to produce salt and water.
From the list of reactions, the only reaction that involves acid and a base with salt and water being the products is the first reaction.
Thus, the neutralization reaction is represented by the equation:

More on neutralization reactions can be found here: brainly.com/question/20038776
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<u>Answer:</u>
<u>For a:</u> The empirical formula of the compound is 
<u>For b:</u> The empirical formula of the compound is 
<u>Explanation:</u>
We are given:
Percentage of P = 43.6 %
Percentage of O = 56.4 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of P = 43.6 g
Mass of O = 56.4 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Phosphorus =
Moles of Oxygen = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.406 moles.
For Phosphorus = 
For Oxygen = 
Converting the moles in whole number ratio by multiplying it by '2', we get:
For Phosphorus = 
For Oxygen = 
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of P : O = 2 : 5
Hence, the empirical formula for the given compound is 
We are given:
Percentage of K = 28.7 %
Percentage of H = 1.5 %
Percentage of P = 22.8 %
Percentage of O = 56.4 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of K = 28.7 g
Mass of H = 1.5 g
Mass of P = 43.6 g
Mass of O = 56.4 g
To formulate the empirical formula, we need to follow some steps:
- <u>Step 1:</u> Converting the given masses into moles.
Moles of Potassium =
Moles of Hydrogen =
Moles of Phosphorus =
Moles of Oxygen = 
- <u>Step 2:</u> Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.735 moles.
For Potassium = 
For Hydrogen = 
For Phosphorus = 
For Oxygen = 
- <u>Step 3:</u> Taking the mole ratio as their subscripts.
The ratio of K : H : P : O = 1 : 2 : 1 : 4
Hence, the empirical formula for the given compound is 
Answer:
Aluminum atoms are in 3.78 g of aluminum
02214076x10^23)8.4367659370640769254888x10^22 atoms, therefore there are 8.4367659370640769254888x10^22 atoms of Aluminum(Al) present in 3.78 grams of Aluminum(Al).
Explanation:
Answer: ethylene glycol (molar mass = 62.07 g/mol)
Explanation:
Depression in freezing point :
Formula used for lowering in freezing point is,

or,

where,
= change in freezing point
= freezing point constant= 
m = molality
Given mass of solute = 0.807 g
Molar mass of solute=? g/mol
weight of solvent in kg= 11.6 g=0.0116 kg



Thus the solute is ethylene glycol which has same molecular mass as calculated, i.e 62.07 g/mol.
In simple terms a force is what makes anything do move or stay still. Some forces are contact forces and some are non contact. Hope this helps.